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LC Tank question; 'Q' detector — Parallax Forums

LC Tank question; 'Q' detector

TappermanTapperman Posts: 319
edited 2012-06-19 08:29 in Propeller 1
Has anyone written an object to read the 'Q' of an LC-Tank (parallel)?

I think I've found a way to do it, and I don't want to 're-invent-the-wheel', if it has already been written before.

Thanks for your attention and input ahead of time,

... Tim

Comments

  • Beau SchwabeBeau Schwabe Posts: 6,568
    edited 2012-06-16 17:11
    I haven't done anything... I'd be interested to see what you have come up with.

    Most of the stuff that I have done focuses on the peak value near the resonant frequency and since I mostly wind air-coils, they generally will have a higher Q than those with a core. To find the Q you would need to determine the energy levels under the envelope on either side of the resonant frequency. i.e. how much bandwidth your occupying under the target frequency.
  • Duane C. JohnsonDuane C. Johnson Posts: 955
    edited 2012-06-16 17:45
    One method is to use a precision oscillator and a variable resistor.
    1. Set the frequency to resonance.
    2. Vary the resistor until the voltage across the parallel LC circuit is 1/2 the driving voltage.
    3. The Q is calculated as R/(impedance of either the L or C)

    I'm not sure this is completely rigorous but it's close.

    Duane J
  • TappermanTapperman Posts: 319
    edited 2012-06-19 08:27
    I haven't done anything... I'd be interested to see what you have come up with.

    Well, I'm still testing some of this out. But I do have a document or two which help show the direction I'm headed. Since you have steered me in the right direction in the past, I thought your review of this material would be very helpfull. And I'm always looking for a little 'ego' stroking too!

    Anyway, more on this later

    ... Tim
  • TappermanTapperman Posts: 319
    edited 2012-06-19 08:29
    I'm not sure this is completely rigorous but it's close.

    Duane J

    I think I'll use this to test my objects (how accurate are they) ... Thanks for the info

    ... Tim
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