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I need a little math help now — Parallax Forums

I need a little math help now

metron9metron9 Posts: 1,100
edited 2007-11-05 05:29 in General Discussion
I have gone back to an older project spured on by another question from a poster on these boards.

This link shows a bandpass circuit, i connected it up and tested it and it works great. It gives the formulas to calculate the resistors and I would like to put it into a spreadsheet so I can build a dozen of them to run a·LED equalizer wall display using 12 - 4 foot bars of LED's to make a digital wall mounted equalizer·but I don't fully understand what some of the variables are. (note I saw a book today by Trump that said think BIG so I am giving that a try on a small scale)

For example to calculate R1

R1 = Q / (G*C*2*Pi*F) = 8/(65 * .00000001 * 6.28 * 1700) = 1152 or 1.1K


Dont know what G is and wether C is equal to the formula shown above this one (on the link)

Center Frequency = Square Root of (Lower Frequency * Upper Frequency)
Also F i think would be frequency but if C=center frequency then what is F?

R2 and R3 calculations are

R2 = Q / ((2*Q^2)-G)*C*2*Pi*F) = 8/((128-65) * .00000001 * 6.28 * 1700) = 1189 or 1.2K
R3 = (2*Q) / (C*2*Pi*F) = 16 / (.00000001 * 6.28 * 1700) = 150K

http://www.circuitdb.com/circuits/id/162


If someone could help me with that I could then continue the project.

Ahh gees, one trip to the bathroom and I think i came up with the answer to C and F,·C=capacitor·and F=Center frequency
Still don't see what G is though.




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Think Inside the box first and if that doesn't work..
Re-arrange what's inside the box then...
Think outside the BOX!

Post Edited (metron9) : 11/5/2007 4:51:30 AM GMT

Comments

  • Tracy AllenTracy Allen Posts: 6,666
    edited 2007-11-05 05:29
    It would be the Gain of the amplfier at the center frequency. Yes, C would be the capacitance and F the frequency and Q the Q factor (sharpness of filter). In general, circuits with higher gain and higher Q will require more accurate R and C values, and a wider bandwidth for the op-amp(s).

    There is a nice application note, "Filter Design in 30 Seconds", search for SLOA093 on the Texas Instruments web site.

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    Tracy Allen
    www.emesystems.com
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