Need help moving 2 1-byte variables into a Long

Steel

This code is not working for me:

VAR
·· Long·· X_VALUE
·· Byte·· Buffer[noparse][[/noparse]2]


PUB
·· Buffer[noparse][[/noparse]0] := $FF
·· Buffer[noparse][[/noparse]1] := $FF

· X_VALUE[noparse][[/noparse]15..8] := Buffer[noparse][[/noparse]0]
· Y_VALUE[noparse][[/noparse]7..0] := Buffer[noparse][[/noparse]1]


...I thought that since DIRA and OUTA are pin addressable, that variables would be to := ?

How do you concantenate 2 byte variables into 1 long variable?

Thanks
Shaun
·

Mightor

Steel said...
This code is not working for me:
.
.
How do you concantenate 2 byte variables into 1 long variable?

Thanks

Shaun

A long is 4 bytes, err long. Did you mean to use a Word sized variable, they're two bytes big.
For a word it would be something along the lines of

varname.Byte[noparse][[/noparse] 0 ] = buffer[noparse][[/noparse] 0 ]
varname.Byte[noparse][[/noparse] 1 ] = buffer[noparse][[/noparse] 1 ]

Gr,
Mightor

▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔
| To know recursion, you must first know recursion.

Steel

Thanks, Mightor.

The var is a long because I am using it in other places...but the same principle applies.

Thank you!

deSilva

Steel said...
...I thought that since DIRA and OUTA are pin addressable, that variables would be to := ?

No. As SPIN does not really know of arrays, it cannot distinguish whether you use a straight variable or the start element of a vector. It is different with reserved names as OUTA, INA,....

Steel said...
How do you concantenate 2 byte variables into 1 long variable?

Be careful as the Prop is a little-endian machine..