Solenid circuit modification
Siri
Posts: 220
·In my project I would like to have LED show the state of the solenid so I plan in modifying the circuit which also
has a revrse biased diode to sub the spike generated by the collapsing magnetic field.
My question is can I add and LED(diode) in parallel in the other direction so it will light up when the solenoid is energised.
Is there any reason NOT to place the dioded in parallel.
The circuit diagrams are attached.
has a revrse biased diode to sub the spike generated by the collapsing magnetic field.
My question is can I add and LED(diode) in parallel in the other direction so it will light up when the solenoid is energised.
Is there any reason NOT to place the dioded in parallel.
The circuit diagrams are attached.
Comments
No circuit diagram was attached, unfortunately.
Regards,
Bruce Bates
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I am sorry the attachment failed and I will try it again so you and others can see and help me out.
Siri
Thanks,
Siri
You must add a series resistor to limit the current through the LED.
With the circuit as you've shown it, the LED will glow brightly once
and the release all its magic smoke.
When you turn off the FET controlling the solenoid, the solenoid
current will try to continuing flowing. The only path available is
through the snubber diode you have connected across the solenoid.
When the snubber diode conducts, it will present a reverse voltage
of roughly 0.7 volts to the LED and associated resistor. I'm certain
that the LED can tolerate being reverse biased by 0.7 volts.
phil
Post Edited (phil kenny) : 6/10/2007 5:58:32 PM GMT
This is the second time i've come across "magic smoke" in these forums. Rest assured there is no magic or wizardry involved herin.·I'm an Electronics engineer, simply put, when you present any electrical/electronic device with more electrical current and/or voltage than it's rated at it will generate more heat than it was designed·to dissipate·and will begin the thermal runaway process. Present too much electrical potential and it could explode! example would be a 2V LED vs a 12V battery, the result without a volt/current limit resistor? POP!
Reverse biasing a power diode on a coil of wire like a solenoid will protect the switching ciruitry from a potentially dangerous reverse polarity voltage spike. Keeping the LED in polarity with the solenoid will work fine as long as you use a resistor in series with the LED (not the protection diode). generally, use a 220-500 ohm for 5V devices, 500-1K ohm for 12V, 1K-2K ohm for 24V.
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Definetly a E3 (Electronics Engineer Extrodinare!)
"I laugh in the face of imposible,... not because i know it all, ... but because I don't know well enough!"
when integrated circuits are manufactured. Worth looking at.
http://en.wikipedia.org/wiki/Magic_smoke
phil
Post Edited (phil kenny) : 6/10/2007 6:54:36 PM GMT
Thessaurus.com
Dictionary.com
Encyclopedia.com
Howstuffworks.com
Are examples of valid sources, i'm sure there are more, but Wikipedia is not one of them. I recall a few times loking for things on wikipedia and these are things i know in detail, search results came back as "scatterbrained" some definitions for my search terms look as if they were written by a 4th grader, bad grammar/spelling. I wouldn't trust it...
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Definetly a E3 (Electronics Engineer Extrodinare!)
"I laugh in the face of imposible,... not because i know it all, ... but because I don't know well enough!"
I have let everyone know that I was using an LED rated at 12V,20mA which has a built in resistor from Radio Shack - if anyone intersted in this part #276-209.That was why the resistor was omitted in the circuit.
I should have stated in the initial posting.
I am thankful to all of you who replied my posting and the explanations has taught me a little more.
Thanks once again to a nice bunch of electronic wizzards.
Siri