SXB pin state read / write...

FORD

Hi all,

I would like to read the state of an input·pin, and immediately put it inverted onto an output pin.

something like...

output <> input

what is the correct way to do this in sxb ?
i have tried a few methods, and get syntax type errors.
i dont want to have to resort to if/then statements etc.

any help appreciated.

cheers,
Chris Anderson
Western Australia
·

JonnyMac

Give this a try, Chris:

  INPUT ioPin
  newState = ~ioPin
  ioPin = newState
  OUTPUT ioPin

I tried moving the inverted input directly to the output register but it doesn't compile as expected -- use a bit variable for temporary storage of the new state.

Post Edited (JonnyMac) : 4/29/2007 1:44:03 PM GMT

FORD

thanks Jon,

will try that tomorrow...

about top post another question if you wouldnt mind looking at it, i'm not at work, so cant check it myself (no tools here at home).

cheers, chris.

Bean

Chris,
Is the input pin and the output pin the same pin ? Jon code makes that assumption.
If they are different pins then just use "OutPin = ~InPin"

Bean.

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JonnyMac

Oi... I could have sworn that he wanted the same pin (that's what I get for working so early on a Sunday...), but looking at it now I think you're right, Terry. Chris, this will work:

outPin = ~inPin

And it turns out it will work fine in either case -- whether you're using the same pin or not. If using the same pin you'll need to deal with the output state after; if those pins (when using two) have previously been declared then you just need the one line.

Post Edited (JonnyMac) : 4/29/2007 7:33:02 PM GMT