Can anyone explain or duplicate this error

bambino

·[noparse][[/noparse]code "test debug"
obj
·· com : "SimpleDebug"
·· pad : "Keyboard"
Var
·· long stack[noparse][[/noparse]9]
·· byte thing
·· byte cog
pub Main
·· cog := (cognew(com.start(115200),@stack)+1)
·· pad.start(27,26)
·· repeat
···· thing := new.key
···· com.putc(thing)
···· waitcnt(25_000+cnt)
···outa[noparse][[/noparse]16]
/code]
This code (done from memory,may not be exactly what I got at home) works,
but when I take out the line outa[noparse][[/noparse]16] I get nothing when I run the program.
This isn't how I intend to use the routine, I actually have it working without the outa in a subroutine instead of main. I am just curious why the loop will not execute without the outa statement doing nothing here, when it seems like it would never get called anyway.

Graham Stabler

need to see the actual code I think

bambino

I will try to bring it in tomarrow!!

bambino

Here is what I was using to get the error.

Graham Stabler

unfortunately I don't have any serial set up to test properly.

As you rightly say it should never run the outa line. I wonder if the problem is the waitcnt, this is the only command that could go wrong if the time was too short. I wonder if increasing the delay would change anything. Grasping at straws, most confusing.

Graham

Paul Baker

Spawning a new cog should be encapsulated within the object in which the routine resides. If you open the Keyboard.spin you will see it spawns a cog to handle the keyboard. You are spawning a cog, which spawns a cog then lets the former cog die. You should instead replace the first line with "pad.start(27,26)".

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Paul Baker
Propeller Applications Engineer

Parallax, Inc.

bambino

Thanks Graham,Paul

Sorry about the delay(no internet at home).

I will try that when I get home out of curiosity, as I stated before when I put the routine in a sub routine it worked fine.(Then I found the monitor object last night and I had to slap myself for recreating the wheel here).