Capacitor Problem
bennettdan
Posts: 614
· If I combine a .022uf cap and a .o1uf cap in series would I get a .0145uf cap reading? I think I am doing the math right.
Comments
You should get 0.006875 uF
The formula is Ct = (C1 x C2)/(C1 + C2). Identical to the formula for resistors in parallel.
equals
Ct = 1/(1/C1 + 1/C2)
which works out to
Ct = (C1 x C2)/(C1 + C2)
Either way the answer is 6.875 nF