You should solve·for CT -- not the reciprocal of it (1 / CT).· Nobody does nanofarads; capacitance is expressed as millifarads [noparse][[/noparse]mF], microfarads [noparse][[/noparse]uF], or picofarads [noparse][[/noparse]pF].
Hey bullwinkle I played with the formula and I understand how to plug the values in now thanks for your help. one more question for future reference what is the parallel formula for caps?
Thanks guys the reason I am asking I have chip that is controlled by my stamp that needs a RC frequency of around 15khz with a 10k pot so I need about a .06uf cap by my figures, but does caps in series cause problems with the RC curcuit or does it really matter to have more than one cap to make the curcuit you need?
I would try to select the nearest standard value capacitor that gets you close to the frequency you want with a standard value resistor, pick the next lowest standard value resistor and add a series pot to adjust the frequency to what you want. You can always measure the actual pot value and substitute a second fixed resistor once you've got the frequency where you want it.
Typically, in an RC-circuit, one uses a potentiometer instead of searching for the perfect capacitance.· It's OK to parallel for value (or series, for that matter), if your "junk-box" isn't brimming with goodies.· Are lives at stake?· Just run with it, man.
Comments
You should get 0.006875 uF
The formula is Ct = (C1 x C2)/(C1 + C2). Identical to the formula for resistors in parallel.
equals
Ct = 1/(1/C1 + 1/C2)
which works out to
Ct = (C1 x C2)/(C1 + C2)
Either way the answer is 6.875 nF