Math Problem Find the Arc
metron9
Posts: 1,100
Some of you folks are pretty smart when it comes to electronics and that makes you pretty good at math as well I would think.
I need to know the diameter of a circle given the following:
If you have a circle and slice off 1/16 of an inch and the length of that slice is 22 inches.
Could someone give me the equasion to calculate the diameter of the circle?
▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔
Think outside the BOX!
I need to know the diameter of a circle given the following:
If you have a circle and slice off 1/16 of an inch and the length of that slice is 22 inches.
Could someone give me the equasion to calculate the diameter of the circle?
▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔
Think outside the BOX!
Comments
Attached is a pdf of my understand of your question
▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔
·1+1=10
Post Edited (Paul Baker) : 12/2/2005 4:57:56 PM GMT
Paul's take on the original question is how I interpreted it as well....
Ryan
▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔
Ryan Clarke
Parallax Tech Support
RClarke@Parallax.com
If the length of a slice is 22 inches that is the same as 1/2 diameter...
2x22=44 inches diameter
It would be easier to understand what you are asking if you had a drawing attached..
Bob N9LVU
Post Edited (Robert Kubichek) : 12/2/2005 8:16:28 PM GMT
Sorry, the calculation I gave you is actually the radius of the circle, to calculate the diameter, multiply the result by 2 or 1936.0625 inches or 53.78 yards or ~ 1/2 a football field. Good luck designing a compass large enough to draw the arc, since youll need 26.89 yards of string and a large enough space to sweep it for a 22" chord.
▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔
·1+1=10
Post Edited (Paul Baker) : 12/2/2005 5:34:18 PM GMT
So here is my challenge- interpret the original question in as many ways as possible-
Ryan
▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔
Ryan Clarke
Parallax Tech Support
RClarke@Parallax.com
So, the chord length is 22", the depth of the chord to arc is 1/16", and you want the diameter of the circle???
c is cord length, or 22"
h is the distance of middle of chord to middle of arc segment that the cord ends bisect, or .0625"
solve for (r)adius
(c2+4h2)/(8h) = r
((22*2) + (4x.0625*2)) / (8x.0625)= 968.0313" radius
( 484 + 0.015625) / .5 = 968.0313" radius
968.0313 x 2 = 1936.0626" diameter...
Then the diameter is 1,936.0626" and radius is 968.0313"
It has been awhile, I had to go back and my check my book...
Bob N9LVU
I had this problem last year and I was able to get my math genius daughter to calculate it for me , I made a little program but due to my lack of bookeeping skills I lost it. It is for a cosmetic display label we are working on to fit a molded plastic display. Now I can order the die and distort the image to the corrrect arc.
As I remember the formula I was given before, I thought it had an ARCTAN function in it wich is maby what your formula above is. (I only have an 8th grade education in math as I was a hippy back then and did not think I would ever need to learn all that stuff.)
It's fun to pull up those old math skills I bet.
▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔
Think outside the BOX!
Yup
Check this link, it has all you would need and more!
mathforum.org/dr.math/faq/faq.circle.segment.html
Bob N9LVU
▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔
·1+1=10