basic math #2
i have another dumb question,hoping for some direction
chapter 4, basic analog and digital
i understand more than i dont. the problem i am having is
when we look at step voltage an 8 bit system we end up with step voltage rounded off to "20mv"
with the resistive ladder and d/a convertion we use an 4 bit system our step voltage increases to "200mv"
the Calc_volt subroutine seems to be the same,
what am i missing?
i understand the circuit and how the code works but trying to make sence of the multible of ten on the step voltage
the one thing i did not consider was the circuit math itself.
is this were i should be looking ?
thanks for all your help
jasper
chapter 4, basic analog and digital
i understand more than i dont. the problem i am having is
when we look at step voltage an 8 bit system we end up with step voltage rounded off to "20mv"
with the resistive ladder and d/a convertion we use an 4 bit system our step voltage increases to "200mv"
the Calc_volt subroutine seems to be the same,
what am i missing?
i understand the circuit and how the code works but trying to make sence of the multible of ten on the step voltage
the one thing i did not consider was the circuit math itself.
is this were i should be looking ?
thanks for all your help
jasper
Comments
·· Which version of the manual are you using?· Please list version and page number when referring to the manuals.· I cannot seem to find what you refer to in Basic Analog and Digital V1.3.
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Chris Savage
Parallax Tech Support
csavage@parallax.com
Basic Analog and Digital V1.3. page 73 figure 4-3
first the amps 20 ma basic stamp output
then the resistors 13k the circuit to binary #1
now the volts 5 a given on my board
20 ma X 13k = 26
5 / 26 = .190 volts per step (+- 10 %)
the answer was in the circuit
needed to buy cheap "dvom"