- Interface to Allen Bradley 42kl-u2lb-f4 Please Review
Mrdavidjenkins
Posts: 49
Good Morning,
I·would like to use a Allen-Bradley Photoreflective ·42kl-u2lb-f4 to count the strokes on a machine.· I would like to put a reflector on a arm, count when the unit sees a reflection and then doesn't see the reflector.··
This is a fairly expensive unit, and I am concerned with the amperage to the units.· I don't want to blow them up, so I'd appreciate any imput you might have.
Attached is a copy of the diagram I would like to use.· Below that are a couple links I would like to use.
Does anyone see problems with this design?·
http://www.ab.com/catalogs/c114/1pho/104357.pdf
http://www.radioshack.com/product.asp?catalog%5Fname=CTLG&product%5Fid=273-1691
http://www.radioshack.com/product.asp?catalog%5Fname=CTLG&category%5Fname=CTLG%5F011%5F002%5F013%5F000&product%5Fid=275%2D249&site=search
Thanks !
I·would like to use a Allen-Bradley Photoreflective ·42kl-u2lb-f4 to count the strokes on a machine.· I would like to put a reflector on a arm, count when the unit sees a reflection and then doesn't see the reflector.··
This is a fairly expensive unit, and I am concerned with the amperage to the units.· I don't want to blow them up, so I'd appreciate any imput you might have.
Attached is a copy of the diagram I would like to use.· Below that are a couple links I would like to use.
Does anyone see problems with this design?·
http://www.ab.com/catalogs/c114/1pho/104357.pdf
http://www.radioshack.com/product.asp?catalog%5Fname=CTLG&product%5Fid=273-1691
http://www.radioshack.com/product.asp?catalog%5Fname=CTLG&category%5Fname=CTLG%5F011%5F002%5F013%5F000&product%5Fid=275%2D249&site=search
Thanks !
Comments
The Jpg was a bit fuzzy, but based on what could make out, you will be OK with one change.
The relay is within the capability of the photocell, current wise ( max 100 mA) and the isolation provided by the relay will keep the Stamp safe.
You'll probably have to change the 220 ohm resitor in the relay coil lead to 50 ohms. That value plus the relay's 200 ohms will limit the circuit current to about 60 mA based on the 15 v power supply.
Cheers
Thanks
Dave