I give up..

Jayguy5000

I am trying to make a simple program that will look like such..

1 = $1
2 = $2

(and so on)

10 = $A

---

' the program i wrote is


counter VAR Word
one VAR Word
one = 1

FOR counter = 1 TO 20
DEBUG DEC one," ", HEX? one
one = one + 1
PAUSE 500
NEXT

' the outcome was

1 one = $1

so my question is, how can i take out the "one" so i only see 1 = $1

( the point of this program is pointless, I just want to see every number in decimal form translated to hexidecimal )

Chris Savage

Hello,

·· Modify the code to look like this:

' {$STAMP BS2}
' {$PBASIC 2.5}
counter VAR Word
one VAR Word
one = 1
FOR counter = 1 TO 20
DEBUG DEC one,"=$", HEX one, CR
one = one + 1
PAUSE 500
NEXT

·basicaly remove the question mark from the HEX formatter, and put in the equals sign and dollar sign you specified in the quotes.

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Chris Savage
Parallax Tech Support
csavage@parallax.com

Ryan Clarke

And for fun you could do octal. [noparse];)[/noparse]

Ryan

Jon Williams

To get the code to indicate hexidecimal, use the IHEX modifier like this:

idx··· VAR··· Byte

Main:
· FOR idx = 1 TO 20
··· DEBUG DEC idx, "·= ", IHEX idx, CR
··· PAUSE 500
· NEXT

Note that you don't need the one = one + 1 line in the program since FOR-NEXT automatically increments the control variable, and that's what's being used for output.· And since you've set a high limit of 20 with the FOR-NEXT loop, you only need a Byte.· In my opinion variable conservation should always be practiced -- even in throw-away demos.


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Jon Williams
Applications Engineer, Parallax

Post Edited (Jon Williams (Parallax)) : 5/31/2005 9:24:28 PM GMT

nick bernard

idx var word...

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Byte walks into a bar and orders a pint. Bartender asks him "What's wrong?"
Byte says "Parity error." Bartender nods and says "Yeah, I thought you looked a bit off."

KenM

Nick,

Did you get hit in the head with a bowling ball? (rib jab)· I know that YOU know a byte goes up to 255, a word is not needed.

nick bernard said...
idx var word...

Ryan Clarke

Unless that was "word" as in Vanilla Ice "word" [noparse];)[/noparse]

Ryan