stepper motor's detent torque decreased
Whelzorn
Posts: 256
I have 2 stepper motors that are exactly the same. I ran one of them for about 3 minutes at the voltage it specifies (12v) (and the power supply gave more than enough current), under quite a bit of load, but the stepper could handle it without much problem. It is the only one out of the two I had run, and the detent torque on the one I had running for 3 minutes is less than the one I hadn't run at all. (detent torque·[noparse][[/noparse]I think]·is the amount of force required to turn the shaft without any power applied to the motor). Is this normal/ok? I'm hoping it's not that the coils are being ruined under that much force...
BTW I was running the motor in unipolar mode if it matters.
Thanks,
Justin W.
Post Edited (Whelzorn) : 2/23/2005 5:01:35 PM GMT
BTW I was running the motor in unipolar mode if it matters.
Thanks,
Justin W.
Post Edited (Whelzorn) : 2/23/2005 5:01:35 PM GMT
Comments
It can be useful to judge if the motor will hold a load while the coils are turned off, thus saving power and reducing the heat generated by the motor after it reaches it's position. I can't see this changing by use, unless heat is a factor reducing friction from the bearings, or the magnetism. If the motor is overloaded, it simply will not turn, and there is nothing there to damage. I'll do a test with mine to see if there is any difference after the motor has been run. I still think there is nothing to be concerned about.
kelvin
thanks again,
Justin
No one seems to be able to help me. Some people are saying PIN 10 goes to + of you power source, others say it goes to -, parallax documentation is saying -, I don't really know what else the problem could be.
Thanks
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Johnny
thansk
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Johnny
The -ve terminal of your supply needs to go to the system ground - which should also be connected to VSS on the stamp and pin 9 on the buffer chip.
All the buffer chip can do is connect selected ones of its output pins to pin 9, grounding them. It's up to you to put your load beween the output pin and the supply. The buffer chip can only 'pull down' - it can't drive any current out of its pins.
(At the moment, all you're doing is attaching all of your stepper wires to the same place - ground. No voltage from ground to ground, so no current flows anywhere, and nothing happens to your motor. )
Is there a good intro guide to transistors on the web / in a Parallax book? This honestly isn't as hard as you're making it [noparse]:)[/noparse]
Steve
Rick
Unless you have a use for detent torque, it is a non issue. When you have the coils 'powered' and are not getting the same holding torque, then you might have some concern.
kelvin