leds and bs2 follow up
rr
Posts: 63
can i power 2 leds through one pin if they in parallel...
i am trying to power them through a 100k solid state pot that i will pulse through another pin.
i am using the leds for back lighting and it makes more even light with at least two leds
any help or suggestions???
i am trying to power them through a 100k solid state pot that i will pulse through another pin.
i am using the leds for back lighting and it makes more even light with at least two leds
any help or suggestions???
Comments
What is it exactly you are trying to do? It sounds like you are trying to vary LED brightness via your stamp, is this correct?
Ken
AG
I am also interested in wiring a circuit this way! Would you draw up the circuit and post it here so I can view it as well.
Thanks and Happy New Year!
Luke
AG·
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Jon Williams
Applications Engineer, Parallax
Dallas, TX· USA
AG
i am new to this stuff so let me get this straight.
do i want to hook up the stamp pin to the input side of one of the gates(A)
and the led circuit should be coming off the other side of the gate (output,Y)
i am gathering that i hook up the vss to the ground, but do i also hook up the vdd to the vcc???
thanks...
but i would like to know about vcc voltage supply
i dont need to worry about vcc because i only need a ground to compleat the led circuit???
or do i need 5v to power the chip in some way
· Here's how it works.··The input pins of the 7404 are labeled "A"; the outputs are labeled "Y".· So, the way a 7404 (an inverter) works is that it for any input at "A", the corresponding "Y" output will be·"A-not."· So, if·"A1" = 5V (or a logic of 1), then "Y1" will equal 0V.·
· The source of the LED is the 5V source from either Vdd, or any other 5V source available.· The Vcc for the·7404 is also 5V.· The·BS2 pin sends a signal, either logic 1 or 0 to·A1 of the 7404.· If·the BS2 sends a·0 (0V) to A1, then Y1 will have logic 1 (5V).··For this state, no current will flow through the LED.· If the BS2 sends a logic 1 (5V) to A1, then 0V will be present at Y1, thereby allowing current to flow from the 5V source, through the 330 ohm resistor, and through the LED.·
· Just a note about TTL chips, before running any current into·them, they need to be powered by 5V at Vcc and grounded.· Otherwise you will probably fry the chip.· Also, if you have never used them, they are very inexpensive, about 30 cents each.· Good luck.· Feel free to ask if you have any more questions.
AG