shiftout question

Archiver

I need to shift out eleven bits

3 address bits, then 8 data bits

Is there a way to do this using shiftout and a two digit hex number?

so in effect I need to send
a2,a1,a0,d7,d6,d5,d4,d3,d2,d1,d0

it wants to see a2 as the first bit, and I don't quite understand how to
do this

say I shiftout hex 3
msb first
this will send
0000 0011 starting left to right - most sig thru least correst

and if I were to use lstfirst

it would send
1100 0000 correct?

so is there an easy way to do this?

I need to send msbfirst, except skip of the most sig 5 bits

thanks

Archiver

Try this:

SHIFTOUT p_data, p_clock, MSBFIRST, [noparse][[/noparse]a << 5 \3, d]

or,

SHIFTOUT p_data, p_clock, MSBFIRST, [noparse][[/noparse]a << 5 + d \11]


Regards,

Steve

On 16 Nov 02 at 5:39, rad0 wrote:

> I need to shift out eleven bits
>
> 3 address bits, then 8 data bits

Archiver

On 16 Nov 02 at 5:53, S Parkis wrote:

> Try this:
>
> SHIFTOUT p_data, p_clock, MSBFIRST, [noparse][[/noparse]a << 5 \3, d]
>
> or,
>
> SHIFTOUT p_data, p_clock, MSBFIRST, [noparse][[/noparse]a << 5 + d \11]


Correction to last line:

SHIFTOUT p_data, p_clock, MSBFIRST, [noparse][[/noparse]a << 8 + d << 5 \11]

Sorry for the confusion.

Steve