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Ray-
Assuming this truth table:
last this desired
time time result
0 0 0
0 1 1
1 0 0
1 1 0
And that you're working with a BS1:
SYMBOL this = BIT0
SYMBOL last = BIT1
SYMBOL result = BIT2
last = 1
again:
this = PIN1
result = ~last & this
DEBUG CR,BIN1 last, BIN1 this, BIN1 result
last = this
GOTO again
Regards,
Steve
On 31 Oct 01 at 20:16, Ray Gonzalez wrote:
> Hi Guys I need help, I have an application that need to process and
> input just one time even if the input stay on for more than one scan...
Assuming this truth table:
last this desired
time time result
0 0 0
0 1 1
1 0 0
1 1 0
And that you're working with a BS1:
SYMBOL this = BIT0
SYMBOL last = BIT1
SYMBOL result = BIT2
last = 1
again:
this = PIN1
result = ~last & this
DEBUG CR,BIN1 last, BIN1 this, BIN1 result
last = this
GOTO again
Regards,
Steve
On 31 Oct 01 at 20:16, Ray Gonzalez wrote:
> Hi Guys I need help, I have an application that need to process and
> input just one time even if the input stay on for more than one scan...
Comments
one time even if the input stay on for more than one scan I remember seeing a
little code that did just that something like
b1=b0
b0=pin1
b2=b1^ pin1
this one give me a b2=1 on the 2 edges of pin1 I like to have b2=1 only on the
rising edge of pin1
Thank you
Ray
[noparse][[/noparse]Non-text portions of this message have been removed]
>input just one time even if the input stay on for more than one scan
>I remember seeing a little code that did just that something like
>
>b1=b0
>b0=pin1
>b2=b1^ pin1
>
>this one give me a b2=1 on the 2 edges of pin1 I like to have b2=1
>only on the rising edge of pin1
Maybe...
x1=x0
x0=pin1
x2=x1^ x0 & x0 ' <<<< add the & x0 to single out the rising edge.
I changed the variable to "x" to avoid confusion with the reserved
BS2 names, "b0" to "b25". ("b0" to "b13" on the BS1).
For your program you only need bit variables
x0 var bit
etc.
-- Tracy
changed back, if not return.
On Wed, 31 Oct 2001 20:16:36 -0500 "Ray Gonzalez" <reyg@v...>
writes:
> Hi Guys I need help, I have an application that need to process and
> input just one time even if the input stay on for more than one scan
> I remember seeing a little code that did just that something like
>
> b1=b0
> b0=pin1
> b2=b1^ pin1
>
> this one give me a b2=1 on the 2 edges of pin1 I like to have b2=1
> only on the rising edge of pin1
>
> Thank you
> Ray
>
>
> [noparse][[/noparse]Non-text portions of this message have been removed]
>
>
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>
routine in your program it will do what you want if your program isnt to
big
On Thu, 1 Nov 2001 21:21:07 -0600 kelvin l schroeder <kls48@j...>
writes:
> you could use a gosub routine on a state change, see if the pin has
> changed back, if not return.
>
> On Wed, 31 Oct 2001 20:16:36 -0500 "Ray Gonzalez"
> <reyg@v...>
> writes:
> > Hi Guys I need help, I have an application that need to process
> and
> > input just one time even if the input stay on for more than one
> scan
> > I remember seeing a little code that did just that something like
> >
> > b1=b0
> > b0=pin1
> > b2=b1^ pin1
> >
> > this one give me a b2=1 on the 2 edges of pin1 I like to have b2=1
>
> > only on the rising edge of pin1
> >
> > Thank you
> > Ray
> >
> >
> > [noparse][[/noparse]Non-text portions of this message have been removed]
> >
> >
> > To UNSUBSCRIBE, just send mail to:
> > basicstamps-unsubscribe@yahoogroups.com
> > from the same email address that you subscribed. Text in the
> > Subject and Body of the message will be ignored.
> >
> >
> > Your use of Yahoo! Groups is subject to
> > http://docs.yahoo.com/info/terms/
> >
> >
>
> To UNSUBSCRIBE, just send mail to:
> basicstamps-unsubscribe@yahoogroups.com
> from the same email address that you subscribed. Text in the
> Subject and Body of the message will be ignored.
>
>
> Your use of Yahoo! Groups is subject to
> http://docs.yahoo.com/info/terms/
>
>
Ray
Original Message
From: "Ray Gonzalez" <reyg@v...>
To: <basicstamps@yahoogroups.com>
Sent: Wednesday, October 31, 2001 8:16 PM
Subject: [noparse][[/noparse]basicstamps] TOGGLE INPUT
> Hi Guys I need help, I have an application that need to process and input
just one time even if the input stay on for more than one scan I remember
seeing a little code that did just that something like
>
> b1=b0
> b0=pin1
> b2=b1^ pin1
>
> this one give me a b2=1 on the 2 edges of pin1 I like to have b2=1 only on
the rising edge of pin1
>
> Thank you
> Ray
>
>
> [noparse][[/noparse]Non-text portions of this message have been removed]
>
>
> To UNSUBSCRIBE, just send mail to:
> basicstamps-unsubscribe@yahoogroups.com
> from the same email address that you subscribed. Text in the Subject and
Body of the message will be ignored.
>
>
> Your use of Yahoo! Groups is subject to http://docs.yahoo.com/info/terms/
>
>
>