Counting using large Numbers
I need to store and be able to recall a number
from BS2 eeprom memory. The number will exceed
the word level. Can someone give me an idea about
working with large numbers and how to read and
write them to eeprom? Should I do it, a single
digit at a time. Any Help Please???
TIA
Gill
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from BS2 eeprom memory. The number will exceed
the word level. Can someone give me an idea about
working with large numbers and how to read and
write them to eeprom? Should I do it, a single
digit at a time. Any Help Please???
TIA
Gill
_________________________________________________________________
Get your FREE download of MSN Explorer at http://explorer.msn.com
Comments
going to display it, a BCD-type concept may work well.
In BCD, binary-code decimal, each base-ten digit is
stored in four bits - same as with hexadecimal. It is
a pain when doing calculations, but may be useful to
store and display long decimal numbers. Please give
more detail on context.
Bob Pence
--- GL Controls <glcontrols@h...> wrote:
> I need to store and be able to recall a number
> from BS2 eeprom memory. The number will exceed
> the word level. Can someone give me an idea about
> working with large numbers and how to read and
> write them to eeprom? Should I do it, a single
> digit at a time. Any Help Please???
>
> TIA
> Gill
>
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Store and act upon a Batch count and keep a
total cycle count. I need to be able to display
the batch count and total count on an LCD
along with storing both in EEprom.
The batch count can be kept to less than 65000
The total will be quite large. Cycle count for
one day could be as much as 57600 (2 Cycles a second)
I was thinking I could store each digit as a seperate
nibble in eeprom. I also could display it using the
same method. I am not sure of the best way to do it.
Thanks
Gill
>What do you need to do with the number? If you are
>going to display it, a BCD-type concept may work well.
>In BCD, binary-code decimal, each base-ten digit is
>stored in four bits - same as with hexadecimal. It is
>a pain when doing calculations, but may be useful to
>store and display long decimal numbers. Please give
>more detail on context.
>
>Bob Pence
>
>--- GL Controls <glcontrols@h...> wrote:
> > I need to store and be able to recall a number
> > from BS2 eeprom memory. The number will exceed
> > the word level. Can someone give me an idea about
> > working with large numbers and how to read and
> > write them to eeprom? Should I do it, a single
> > digit at a time. Any Help Please???
> >
_________________________________________________________________
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>The stamp needs to count Cycles on a machine,
>Store and act upon a Batch count and keep a
>total cycle count. I need to be able to display
>the batch count and total count on an LCD
>along with storing both in EEprom.
>The batch count can be kept to less than 65000
>The total will be quite large. Cycle count for
>one day could be as much as 57600 (2 Cycles a second)
>I was thinking I could store each digit as a seperate
>nibble in eeprom. I also could display it using the
>same method. I am not sure of the best way to do it.
>
>Thanks
>Gill
>
>Gill -
You might consider a factor variable. When the batch counter nearly
approaches overflow, add 1 to the batch counter, and subtract the value you
chose to represent the limit value.
Example in pseudo code -
batch_limit = 32000 '(arbitrary limit in a word size variable)
batch_count = 0
factor = 0
Process:
' Do whatever you need to here on input
If process_ended then End_Process '(set by some external routine)
batch_count = batch_count + 1
If batch_count < batch_limit then Process:
factor = factor + 1
batch_count = batch_count - batch_limit
Goto Process:
End_Process:
'batch_count now contains the remaining items
'factor contains the multiples of batch_limit
END
That should give you a starting point for counting.
Regards,
Bruce Bates
each nibble, just a decimal digit instead of a hex
digit - e.g. 10011001 ('99') stored in an EEPROM byte
would represent decimal ninety-nine, not 128 + 16 + 8
+ 1 = 16*9 + 1*9 = 153 decimal. So to store this
value, you need to convert to decimal, e.g.:
storbyte.HIGHNIB = x//100/10
storbyte.LOWNIB = x//10
WRITE eploc, storbyte
' 255 stored as 01010101 (DEC 55), need
' to account for numbers over DEC 100
' 00 to 99 stored correctly as is
Bob Pence
--- GL Controls <glcontrols@h...> wrote:
> The stamp needs to count Cycles on a machine,
> Store and act upon a Batch count and keep a
> total cycle count. I need to be able to display
> the batch count and total count on an LCD
> along with storing both in EEprom.
> The batch count can be kept to less than 65000
> The total will be quite large. Cycle count for
> one day could be as much as 57600 (2 Cycles a
> second)
> I was thinking I could store each digit as a
> seperate
> nibble in eeprom. I also could display it using the
> same method. I am not sure of the best way to do
> it.
>
> Thanks
> Gill
>
>
>
>
>
> >What do you need to do with the number? If you are
> >going to display it, a BCD-type concept may work
> well.
> >In BCD, binary-code decimal, each base-ten digit is
> >stored in four bits - same as with hexadecimal. It
> is
> >a pain when doing calculations, but may be useful
> to
> >store and display long decimal numbers. Please give
> >more detail on context.
> >
> >Bob Pence
> >
> >--- GL Controls <glcontrols@h...> wrote:
> > > I need to store and be able to recall a number
> > > from BS2 eeprom memory. The number will exceed
> > > the word level. Can someone give me an idea
> about
> > > working with large numbers and how to read and
> > > write them to eeprom? Should I do it, a single
> > > digit at a time. Any Help Please???
> > >
>
>
_________________________________________________________________
> Get your FREE download of MSN Explorer at
> http://explorer.msn.com
>
>
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=====
Regards,
Bob Pence
NOTE: This mail is sent using my wireless phone. Calling me at 1 (610) 563-6198
is preferred to a reply. If replying to this email address, please do not quote
the original message.
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>Store and act upon a Batch count and keep a
>total cycle count. I need to be able to display
>the batch count and total count on an LCD
>along with storing both in EEprom.
>The batch count can be kept to less than 65000
>The total will be quite large. Cycle count for
>one day could be as much as 57600 (2 Cycles a second)
>I was thinking I could store each digit as a seperate
>nibble in eeprom. I also could display it using the
>same method. I am not sure of the best way to do it.
>
>Thanks
>Gill
Hi Gill,
One way is to store numbers up to 10000 in each word, so that two
words will count up to 100,000,000. It is easy to keep track of the
count and display it. At two counts per second, the eeprom would
wear out very fast. Would it be feasible for the program to update
the eeprom count only occasionally, like once every 100 counts, and
at the end of each day? If you have some battery backed RAM, that
would be better. Some real time clock chips have RAM locations
available for you to store data of this sort (with no danger of
wearing it out!).
' pin signal to count on P0, active high
' serial SEETRON led on P1
' values stored in eeprom at locations 0 to 3
XC0 var word ' count, low word
XC1 var word ' count, high word
j var nib ' for lcd digit output
restart:
' read in the old count values
for j=0 to 3
read j,XC0(j)
next
counter:
if in0=0 then counter ' no count yet
' now count 1
XC0=XC0+1 // 10000 ' increment low word modulo 10000
XC1 = XC1+1-(XC0 max 1) ' high word +1 when XC0=0
debug "count = ",dec4 XC1,dec4 XC0,CR
if XC0//100 then lcdshow ' write to eeprom only at 100 counts
eepromwrite:
for j=0 to 3
write j,XC0(j)
next
lcdshow:
' now display the digits on the lcd
serout 1, $4054,[noparse][[/noparse]home] ' home the lcd
for j=3 to 0 ' high word, most sig dig first
serout 1,$4054,XC1 dig j
next
for j=3 to 0 ' low word
serout 1,$4054,XC0 dig j
next
counterwait: ' counter signal debounce
branch in0,[noparse][[/noparse]counter,counterwait]
-- best regards
Tracy Allen
electronically monitored ecosystems
http://www.emesystems.com
mailto:tracy@e...
guys have helped me to understand what I needed to know
to create and use this counter, Thanks again
Gill
_________________________________________________________________
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list. Here's what I sent Gill earlier.
Byte or word x to BCD is as below - mod x by 10^(N+1)
and divide by 10^N to get the 10^N's place, then store
result (which will be 0..9) as nibble. Displaying as
BCD just depends on continuing to deal with the
nibble.
READ eploc, storbyte ' say storbyte is 10011001 for 99
DEBUG DEC storbyte ' no good, displays 153
DEBUG DEC storbyte.HIGHNIB, storbyte.LOWNIB ' ok - 99
However, for you application - as I'd recommend for
any application of BCD, which is fraught with danger
from my viewpoint - consider an alternate
implementation. Keep a running total of up to 10000
cycles, then update two EEPROM bytes to permanently
tally, well, decakilocycles.
cycles VAR WORD
dkcycs VAR WORD
' code
cycles = cycles + 1
IF cycles > 9999 THEN TALLY
RtnFrTly:
' more code
.
.
TALLY:
cycles = cycles - 10000
READ 0, dkcycs.HIGHBYTE
READ 1, dkcycs.LOWBYTE
dkcycs = dkcycs + 1
WRITE 0, dkcycs.HIGHBYTE
WRITE 1, dkcycs.LOWBYTE
GOTO RtnFrTly
When its time to display, just
DEBUG DEC dkcycs, DEC4 cycles ' DEC4 retain leading
0's
This method yields 655359999 cycles, which at 2
seconds per cycles will allow the equipment to run for
41.5 years continuously without rolling over the
count. Also, the EEPROM locations are written to at
most 65536 times, which is less than the 100,000
writes guaranteed on most Stamps, without having to
check for the low byte exceeding 255. Finally, no BCD
interpretation is required, which is always a good
thing. This could be done with a BCD implementation if
more counts are required, in which case an EEPROM
location would be needed as a pointer to the start of
the value, and possibly one for length, because the
data will have to move as writes exceed 100,000.
Bob Pence
> >--- GL Controls <glcontrols@h...> wrote:
> > > Thanks, sounds like you are right on target.
> > > One more thing, Can you tell me which part
> > > is the conversion formula to BCD. I am sure
> > > its in there but I am not sure which part it is?
> > >
> > > Thanks Again
> > > Gill
> > >
> > >
> > >
>
>*******************************************************
> > >
> > > Yes, Binary-Coded Decimal (BCD) stores one digit
> in
> > > each nibble, just a decimal digit instead of a
> hex
> > > digit - e.g. 10011001 ('99') stored in an EEPROM
> > > byte
> > > would represent decimal ninety-nine, not 128 +
> 16 +
> > > 8
> > > + 1 = 16*9 + 1*9 = 153 decimal. So to store this
> > > value, you need to convert to decimal, e.g.:
> > >
> > > storbyte.HIGHNIB = x//100/10
> > > storbyte.LOWNIB = x//10
> > > WRITE eploc, storbyte
> > > ' 255 stored as 01010101 (DEC 55), need
> > > ' to account for numbers over DEC 100
> > > ' 00 to 99 stored correctly as is
> > >
> > > Bob Pence
> > >
> > >
> > >
>
>_________________________________________________________________
> > > Get your FREE download of MSN Explorer at
> > > http://explorer.msn.com
> > >
> >
> >
> >__________________________________________________
> >Do You Yahoo!?
> >Spot the hottest trends in music, movies, and more.
> >http://buzz.yahoo.com/
>
>
_________________________________________________________________
> Get your FREE download of MSN Explorer at
> http://explorer.msn.com
>
=====
Regards,
Bob Pence
NOTE: This mail is sent using my wireless phone. Calling me at 1 (610) 563-6198
is preferred to a reply. If replying to this email address, please do not quote
the original message.
__________________________________________________
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My replies keep getting lost this morning.
Byte or word x to BCD is as below - mod x by 10^(N+1)
and divide by 10^N to get the 10^N's place, then store
result (which will be 0..9) as nibble. Displaying as
BCD just depends on continuing to deal with the
nibble.
READ eploc, storbyte ' say storbyte is 10011001 for 99
DEBUG DEC storbyte ' no good, displays 153
DEBUG DEC storbyte.HIGHNIB, storbyte.LOWNIB ' ok - 99
However, for you application - as I'd recommend for
any application of BCD, which is fraught with danger
from my viewpoint - consider an alternate
implementation. Keep a running total of up to 10000
cycles, then update two EEPROM bytes to permanently
tally, well, decakilocycles.
cycles VAR WORD
dkcycs VAR WORD
' code
cycles = cycles + 1
IF cycles > 9999 THEN TALLY
RtnFrTly:
' more code
.
.
TALLY:
cycles = cycles - 10000
READ 0, dkcycs.HIGHBYTE
READ 1, dkcycs.LOWBYTE
dkcycs = dkcycs + 1
WRITE 0, dkcycs.HIGHBYTE
WRITE 1, dkcycs.LOWBYTE
GOTO RtnFrTly
When its time to display, just
DEBUG DEC dkcycs, DEC4 cycles ' DEC4 retain leading
0's
This method yields 655359999 cycles, which at 2
seconds per cycles will allow the equipment to run for
41.5 years continuously without rolling over the
count. Also, the EEPROM locations are written to at
most 65536 times, which is less than the 100,000
writes guaranteed on most Stamps, without having to
check for the low byte exceeding 255. Finally, no BCD
interpretation is required, which is always a good
thing. This could be done with a BCD implementation if
more counts are required, in which case an EEPROM
location would be needed as a pointer to the start of
the value, and possibly one for length, because the
data will have to move as writes exceed 100,000.
Bob Pence
> >--- GL Controls <glcontrols@h...> wrote:
> > > Thanks, sounds like you are right on target.
> > > One more thing, Can you tell me which part
> > > is the conversion formula to BCD. I am sure
> > > its in there but I am not sure which part it is?
> > >
> > > Thanks Again
> > > Gill
> > >
> > >
> > >
>
>*******************************************************
> > >
> > > Yes, Binary-Coded Decimal (BCD) stores one digit
> in
> > > each nibble, just a decimal digit instead of a
> hex
> > > digit - e.g. 10011001 ('99') stored in an EEPROM
> > > byte
> > > would represent decimal ninety-nine, not 128 +
> 16 +
> > > 8
> > > + 1 = 16*9 + 1*9 = 153 decimal. So to store this
> > > value, you need to convert to decimal, e.g.:
> > >
> > > storbyte.HIGHNIB = x//100/10
> > > storbyte.LOWNIB = x//10
> > > WRITE eploc, storbyte
> > > ' 255 stored as 01010101 (DEC 55), need
> > > ' to account for numbers over DEC 100
> > > ' 00 to 99 stored correctly as is
> > >
> > > Bob Pence
> > >
> > >
> > >
>
>_________________________________________________________________
> > > Get your FREE download of MSN Explorer at
> > > http://explorer.msn.com
> > >
> >
> >
> >__________________________________________________
> >Do You Yahoo!?
> >Spot the hottest trends in music, movies, and more.
> >http://buzz.yahoo.com/
>
>
_________________________________________________________________
> Get your FREE download of MSN Explorer at
> http://explorer.msn.com
>
__________________________________________________
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Spot the hottest trends in music, movies, and more.
http://buzz.yahoo.com/
May I have your permission to use this also?
Ken
with enough thrust, pigs fly just fine.
---- On Tue, 19 Jun 2001, Pence Bob (bobpence_2000@y...)
wrote:
> [noparse][[/noparse]snip]
>
> My replies keep getting lost this morning.
>
> Byte or word x to BCD is as below - mod x by 10^(N+1)
> and divide by 10^N to get the 10^N's place, then store
> result (which will be 0..9) as nibble. Displaying as
> BCD just depends on continuing to deal with the
> nibble.
>
> READ eploc, storbyte ' say storbyte is 10011001 for 99
> DEBUG DEC storbyte ' no good, displays 153
> DEBUG DEC storbyte.HIGHNIB, storbyte.LOWNIB ' ok - 99
>
> However, for you application - as I'd recommend for
> any application of BCD, which is fraught with danger
> from my viewpoint - consider an alternate
> implementation. Keep a running total of up to 10000
> cycles, then update two EEPROM bytes to permanently
> tally, well, decakilocycles.
>
> cycles VAR WORD
> dkcycs VAR WORD
> ' code
> cycles = cycles + 1
> IF cycles > 9999 THEN TALLY
> RtnFrTly:
> ' more code
> .
> .
> TALLY:
> cycles = cycles - 10000
> READ 0, dkcycs.HIGHBYTE
> READ 1, dkcycs.LOWBYTE
> dkcycs = dkcycs + 1
> WRITE 0, dkcycs.HIGHBYTE
> WRITE 1, dkcycs.LOWBYTE
> GOTO RtnFrTly
>
> When its time to display, just
>
> DEBUG DEC dkcycs, DEC4 cycles ' DEC4 retain leading
> 0's
>
> This method yields 655359999 cycles, which at 2
> seconds per cycles will allow the equipment to run for
> 41.5 years continuously without rolling over the
> count. Also, the EEPROM locations are written to at
> most 65536 times, which is less than the 100,000
> writes guaranteed on most Stamps, without having to
> check for the low byte exceeding 255. Finally, no BCD
> interpretation is required, which is always a good
> thing. This could be done with a BCD implementation if
> more counts are required, in which case an EEPROM
> location would be needed as a pointer to the start of
> the value, and possibly one for length, because the
> data will have to move as writes exceed 100,000.
>
> Bob Pence
>
> > >--- GL Controls <glcontrols@h...> wrote:
> > > > Thanks, sounds like you are right on target.
> > > > One more thing, Can you tell me which part
> > > > is the conversion formula to BCD. I am sure
> > > > its in there but I am not sure which part it is?
> > > >
> > > > Thanks Again
> > > > Gill
> > > >
> > > >
> > > >
> >
> >*******************************************************
> > > >
> > > > Yes, Binary-Coded Decimal (BCD) stores one digit
> > in
> > > > each nibble, just a decimal digit instead of a
> > hex
> > > > digit - e.g. 10011001 ('99') stored in an EEPROM
> > > > byte
> > > > would represent decimal ninety-nine, not 128 +
> > 16 +
> > > > 8
> > > > + 1 = 16*9 + 1*9 = 153 decimal. So to store this
> > > > value, you need to convert to decimal, e.g.:
> > > >
> > > > storbyte.HIGHNIB = x//100/10
> > > > storbyte.LOWNIB = x//10
> > > > WRITE eploc, storbyte
> > > > ' 255 stored as 01010101 (DEC 55), need
> > > > ' to account for numbers over DEC 100
> > > > ' 00 to 99 stored correctly as is
> > > >
> > > > Bob Pence
> > > >
> > > >
> > > >
> >
>
>_______________________________________________________________
__
> > > > Get your FREE download of MSN Explorer at
> > > > http://explorer.msn.com
> > > >
> > >
> > >
> > >__________________________________________________
> > >Do You Yahoo!?
> > >Spot the hottest trends in music, movies, and more.
> > >http://buzz.yahoo.com/
> >
> >
>
________________________________________________________________
_
> > Get your FREE download of MSN Explorer at
> > http://explorer.msn.com
> >
>
>
> __________________________________________________
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> Spot the hottest trends in music, movies, and more.
> http://buzz.yahoo.com/
>
> To UNSUBSCRIBE, just send mail to:
> basicstamps-unsubscribe@yahoogroups.com
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in the
> Subject and Body of the message will be ignored.
>
>
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>
>
>
>
original thought and may have resulting from recently
having read Tracy Allen's excellent Stamp II Math
Notes. You'll find the kernel of the idea at:
http://www.emesystems.com/BS2math6.htm
Tracy uses math instead of the limited Stamp IF...THEN
construction, which is always ideal, albeit at the
expense of three math ops. I don't know which is
faster - most likely Tracy's - but since we are
dealing with byte-size EEPROM locations to store the
high word (and so can't just increment the low byte of
the high word without another IF...THEN), I think my
subroutine approach works well. However, I do risk
losing up to 5 1/2 hours of counts on power failure.
Regards
Bob Pence
--- Ken Ambrose <kenzo@u...> wrote:
> Excellent work Pence!
> May I have your permission to use this also?
>
> Ken
>
> with enough thrust, pigs fly just fine.
>
>
>
>
>
> ---- On Tue, 19 Jun 2001, Pence Bob
> (bobpence_2000@y...)
> wrote:
>
> > [noparse][[/noparse]snip]
> >
> > My replies keep getting lost this morning.
> >
> > Byte or word x to BCD is as below - mod x by
> 10^(N+1)
> > and divide by 10^N to get the 10^N's place, then
> store
> > result (which will be 0..9) as nibble. Displaying
> as
> > BCD just depends on continuing to deal with the
> > nibble.
> >
> > READ eploc, storbyte ' say storbyte is 10011001
> for 99
> > DEBUG DEC storbyte ' no good, displays 153
> > DEBUG DEC storbyte.HIGHNIB, storbyte.LOWNIB ' ok -
> 99
> >
> > However, for you application - as I'd recommend
> for
> > any application of BCD, which is fraught with
> danger
> > from my viewpoint - consider an alternate
> > implementation. Keep a running total of up to
> 10000
> > cycles, then update two EEPROM bytes to
> permanently
> > tally, well, decakilocycles.
> >
> > cycles VAR WORD
> > dkcycs VAR WORD
> > ' code
> > cycles = cycles + 1
> > IF cycles > 9999 THEN TALLY
> > RtnFrTly:
> > ' more code
> > .
> > .
> > TALLY:
> > cycles = cycles - 10000
> > READ 0, dkcycs.HIGHBYTE
> > READ 1, dkcycs.LOWBYTE
> > dkcycs = dkcycs + 1
> > WRITE 0, dkcycs.HIGHBYTE
> > WRITE 1, dkcycs.LOWBYTE
> > GOTO RtnFrTly
> >
> > When its time to display, just
> >
> > DEBUG DEC dkcycs, DEC4 cycles ' DEC4 retain
> leading
> > 0's
> >
> > This method yields 655359999 cycles, which at 2
> > seconds per cycles will allow the equipment to run
> for
> > 41.5 years continuously without rolling over the
> > count. Also, the EEPROM locations are written to
> at
> > most 65536 times, which is less than the 100,000
> > writes guaranteed on most Stamps, without having
> to
> > check for the low byte exceeding 255. Finally, no
> BCD
> > interpretation is required, which is always a good
> > thing. This could be done with a BCD
> implementation if
> > more counts are required, in which case an EEPROM
> > location would be needed as a pointer to the start
> of
> > the value, and possibly one for length, because
> the
> > data will have to move as writes exceed 100,000.
> >
> > Bob Pence
> >
> > > >--- GL Controls <glcontrols@h...> wrote:
> > > > > Thanks, sounds like you are right on
> target.
> > > > > One more thing, Can you tell me which part
> > > > > is the conversion formula to BCD. I am sure
> > > > > its in there but I am not sure which part it
> is?
> > > > >
> > > > > Thanks Again
> > > > > Gill
> > > > >
> > > > >
> > > > >
> > >
> >
>
>*******************************************************
> > > > >
> > > > > Yes, Binary-Coded Decimal (BCD) stores one
> digit
> > > in
> > > > > each nibble, just a decimal digit instead of
> a
> > > hex
> > > > > digit - e.g. 10011001 ('99') stored in an
> EEPROM
> > > > > byte
> > > > > would represent decimal ninety-nine, not 128
> +
> > > 16 +
> > > > > 8
> > > > > + 1 = 16*9 + 1*9 = 153 decimal. So to store
> this
> > > > > value, you need to convert to decimal, e.g.:
> > > > >
> > > > > storbyte.HIGHNIB = x//100/10
> > > > > storbyte.LOWNIB = x//10
> > > > > WRITE eploc, storbyte
> > > > > ' 255 stored as 01010101 (DEC 55), need
> > > > > ' to account for numbers over DEC 100
> > > > > ' 00 to 99 stored correctly as is
> > > > >
> > > > > Bob Pence
> > > > >
> > > > >
> > > > >
> > >
> >
>
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You surely have my permission, but I got to thinking
that recently reading Tracy Allen's excellent Stamp II
Math Notes might have influenced me. Turns out the
first code sample in Math Note 6 (at emesystems.com)
implements such a counter in RAM. Tracy increments the
high word using a clever algorithm, whereas I resort
to the Stamp's limited If..Then capability. I think
this is appropriate, though, because I have to deal
with EEPROM storage.
Regards,
Bob Pence
> with enough thrust, pigs fly just fine.
Cool!
--- Ken Ambrose <kenzo@u...> wrote:
> Excellent work Pence!
> May I have your permission to use this also?
>
> Ken
>
> with enough thrust, pigs fly just fine.
>
>
>
>
>
> ---- On Tue, 19 Jun 2001, Pence Bob
> (bobpence_2000@y...)
> wrote:
>
> > [noparse][[/noparse]snip]
> >
> > My replies keep getting lost this morning.
> >
> > Byte or word x to BCD is as below - mod x by
> 10^(N+1)
> > and divide by 10^N to get the 10^N's place, then
> store
> > result (which will be 0..9) as nibble. Displaying
> as
> > BCD just depends on continuing to deal with the
> > nibble.
> >
> > READ eploc, storbyte ' say storbyte is 10011001
> for 99
> > DEBUG DEC storbyte ' no good, displays 153
> > DEBUG DEC storbyte.HIGHNIB, storbyte.LOWNIB ' ok -
> 99
> >
> > However, for you application - as I'd recommend
> for
> > any application of BCD, which is fraught with
> danger
> > from my viewpoint - consider an alternate
> > implementation. Keep a running total of up to
> 10000
> > cycles, then update two EEPROM bytes to
> permanently
> > tally, well, decakilocycles.
> >
> > cycles VAR WORD
> > dkcycs VAR WORD
> > ' code
> > cycles = cycles + 1
> > IF cycles > 9999 THEN TALLY
> > RtnFrTly:
> > ' more code
> > .
> > .
> > TALLY:
> > cycles = cycles - 10000
> > READ 0, dkcycs.HIGHBYTE
> > READ 1, dkcycs.LOWBYTE
> > dkcycs = dkcycs + 1
> > WRITE 0, dkcycs.HIGHBYTE
> > WRITE 1, dkcycs.LOWBYTE
> > GOTO RtnFrTly
> >
> > When its time to display, just
> >
> > DEBUG DEC dkcycs, DEC4 cycles ' DEC4 retain
> leading
> > 0's
> >
> > This method yields 655359999 cycles, which at 2
> > seconds per cycles will allow the equipment to run
> for
> > 41.5 years continuously without rolling over the
> > count. Also, the EEPROM locations are written to
> at
> > most 65536 times, which is less than the 100,000
> > writes guaranteed on most Stamps, without having
> to
> > check for the low byte exceeding 255. Finally, no
> BCD
> > interpretation is required, which is always a good
> > thing. This could be done with a BCD
> implementation if
> > more counts are required, in which case an EEPROM
> > location would be needed as a pointer to the start
> of
> > the value, and possibly one for length, because
> the
> > data will have to move as writes exceed 100,000.
> >
> > Bob Pence
> >
> > > >--- GL Controls <glcontrols@h...> wrote:
> > > > > Thanks, sounds like you are right on
> target.
> > > > > One more thing, Can you tell me which part
> > > > > is the conversion formula to BCD. I am sure
> > > > > its in there but I am not sure which part it
> is?
> > > > >
> > > > > Thanks Again
> > > > > Gill
> > > > >
> > > > >
> > > > >
> > >
> >
>
>*******************************************************
> > > > >
> > > > > Yes, Binary-Coded Decimal (BCD) stores one
> digit
> > > in
> > > > > each nibble, just a decimal digit instead of
> a
> > > hex
> > > > > digit - e.g. 10011001 ('99') stored in an
> EEPROM
> > > > > byte
> > > > > would represent decimal ninety-nine, not 128
> +
> > > 16 +
> > > > > 8
> > > > > + 1 = 16*9 + 1*9 = 153 decimal. So to store
> this
> > > > > value, you need to convert to decimal, e.g.:
> > > > >
> > > > > storbyte.HIGHNIB = x//100/10
> > > > > storbyte.LOWNIB = x//10
> > > > > WRITE eploc, storbyte
> > > > > ' 255 stored as 01010101 (DEC 55), need
> > > > > ' to account for numbers over DEC 100
> > > > > ' 00 to 99 stored correctly as is
> > > > >
> > > > > Bob Pence
> > > > >
> > > > >
> > > > >
> > >
> >
>
>_______________________________________________________________
> __
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> > >
> > >
> >
>
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=====
Regards,
Bob Pence
NOTE: This mail is sent using my wireless phone. Calling me at 1 (610) 563-6198
is preferred to a reply. If replying to this email address, please do not quote
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