Cable length limitation for motor power?
T Chap
Posts: 4,223
I just came up with an RS485 line driver and receiver for 2 cat5 cables to handle hall sensors and encoders which gives very long cable options when needed. Typically the cables I use for 24v brushless DC is 3 conductor 18 stranded tinned copper. I have run up to 50’ before with the standard system but am trying to see if there are any known limitations for cable lengths vs just hooking up a 150’ length and testing. Would 12/14/16 be less loss to make a different at 150’?
Comments
https://www.analog.com/media/en/technical-documentation/product-selector-card/rs485fe.pdf
For the motors, its going to depend on the motor. Do the motors ever stall?
length and the max working current - from that you calculate the max voltage loss - losing a volt or two from 24V
isn't a show stopper, losing 10V would be.
R = r L / A, where r = resistivity of copper 1.68e-8, L = length of wire in metres (counting both directions),
A is the cross-sectional area of copper in square meters.
Its more convenient to use 1.68e-2 and cross section in sq mm.
Put another way 1m of 1sq mm wire has a resistance of about 17 milliohms.
The other check you can do is that the stall current isn't going to set fire to the wiring (there are many
online tables of both wire resistances per unit length and max safe current either enclosed or not).
Another approach to figuring these things is that for the same load, doubling the length of wire requires
its area to be doubled too to maintain the same voltage loss.
You'll soon discover if you do a few calculations that long cable runs work much better with higher voltage
and lower current.
I think the length of the wire does not affect the performance of a motor at all, it just has some resistance so you have voltage loss.
Enjoy!
Mike
You should be able to calculate the wire gauge by the current differential.
spikes and transients encountered with motors, its already close to the limit. Make sure you've got
good decoupling on the driver.
50m is a very long run for high current - so what is the current rating?
http://getcorp.com/technology-overview/#tab-542
If your power supply can provide 10 amps then it is better to have the wire rated for 10 amps. As a minimum I would suggest at least 16gauge, and if that were my project I would use 14guage since it is available for use in heavy duty extension cords.
I realise that this is out of the question now but I would definitely have gone with a distributed approach. Were it not for the fact that I often have to utilise existing servo-motors, I would be using motors with integrated drives.
Another interesting approach would be to use the ODRIVE with a Prop, located near the motor. These are available in 24v or 48v versions.
Very, very cool.
I was working at Polaris in WI, a while back and I would go in to the factory at all kinds of weird hours when production was quiet. I would have to wait at the gate, snow up to my eyeballs FOREVER because I always seemed to arrive when the security guards were doing their rounds. I felt bad for those guys and had the idea...why not have a few constantly patrolling drones with cameras. This charging system would be perfect.
I bet Trump would be better off with this system instead of a wall/fence that will only be tunnelled-under/climbed-over/cut-through anyway
Very nice work.
Heck yeah.
As I think I mentioned in another thread; look at any machine-tool, open collector from a proximity sensor, driving an opto-coupler....16 gauge conductors (occasionally 18 gauge)...milliamps! And there can be dozens if not hundreds of these signal wires. Drives me nuts having to work with this stuff. This is why I want distributed wireless nodes.
+1
👍
"GET has developed the world’s first hardware that can wirelessly charges heavy drones over long distances (dozens of meters). Our technology provides best efficiency by distance and can deliver kilowatts of power wirelessly."
Wait....kilowatts? I can build a totally wireless machine?
percent loss is proportional to P * l^2 / (m * V^2) [ to a first approximation for modest losses ]
So doubling the length requires 4 times the copper, doubling the supply requires 1/4 the copper,
doubling the power doubles the loss percentage (losses go up by a factor of 4), etc etc.
That l-squared term means long cable runs are not usually practical unless the voltage is increased, a not
unsurprising result.
Anything can be wireless.
Dwight:
As of this morning, we are completely wireless here on Schrute Farms. As soon as I find out where Mose hid all the wires, we'll have that power back on.
https://getyarn.io/yarn-clip/1f3157db-5100-41a2-845d-345fe8560727