Prop IO Pin Voltage Drop vs. Current
Vega256
Posts: 197
in Propeller 1
Hey guys,
I've taken some measurements of the nominal open circuit voltage on my prop io pins, and its around 3.2v when high - the voltage drops down to about 2.6 @ around 25mA. Does anyone have any experimentally acquired measurements for v vs i?
I've taken some measurements of the nominal open circuit voltage on my prop io pins, and its around 3.2v when high - the voltage drops down to about 2.6 @ around 25mA. Does anyone have any experimentally acquired measurements for v vs i?
Comments
ALL circuits have some resistance or voltage drop in their outputs, only poor simulators would deliver 10A for instance with zero voltage drop. With the CMOS outputs on the Prop I think the ÖN resistance is around 45 ohms. If you drive an LED or a BJT transistor then the voltage it drops down to doesn't really matter, only the current. When you drive MOSFETs then the voltage matters but in that case they do not draw any static current.
So .... NO PROBLEMS.
That's what I thought, but I dismissed it as a small amount being lost somewhere from within the chip.
It's because Vdd isn't 3.3V; it's 3.21V, and Voh is 3.19V to be more precise.
So can I use 45 ohms for future calculations? I'm guessing this is an approximation since we're talking about non-ohmic CMOS outputs?
Yep. I'm getting a 20mV drop from vdd to io. It's past due time that me and this radioshack mm part ways.
http://forums.parallax.com/discussion/135845/p8x32a-pin-driving-fet-resistance-graph
Regarding the VDD drop you also have the impedance of the vdd connection net, which could explain the ~20mv drop depending on how many active cogs you're running. Furthermore this might be slightly worse for DIP vs QFP/QFN, since there are fewer power connections. There was some mention of double bonding those incoming supply rail ties, but I presume this applies both to DIP and QFP/QFN
Taking the numbers above
(3.3-2.85)/10m = 45 Ohms (worst case)
(3.2-2.6)/25m = 24 Ohms (your measurement aka typical)
Worst case specs cover corner silicon, and highest T and lowest Vcc, so it is common for typicals to be around half of that (as we see here)
When dropping under one third of supply, (as here) CMOS pins are broadly resistive.
No, the resistance is the channel resistance of the output FET on the pin. Yes, it is very resistive (if you don't overload
the pin), its just Rds(on) of a PFET.