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New so need some tutoring

MarkCrCoMarkCrCo Posts: 89
edited 2014-05-01 15:57 in General Discussion
Ok I think there is a simple explanation for this but can't find it on the internet. I have my boe-bot running fine on 4 AA batteries (6 Volt - non-rechargeable). Tried to hook him up to two lithium 3 volt watch batteries (CR2032). He starts up and plays his little initialization tune on the speaker then lurches forward and resets and starts over again. Why is 6 volts from AA batteries not the same as 6 volts from the disk batteries?
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  • PJAllenPJAllen Banned Posts: 5,065
    edited 2014-04-25 06:36
    MarkCrCo wrote: »
    Ok I think there is a simple explanation for this but can't find it on the internet. I have my boe-bot running fine on 4 AA batteries (6 Volt - non-rechargeable). Tried to hook him up to two lithium 3 volt watch batteries (CR2032). He starts up and plays his little initialization tune on the speaker then lurches forward and resets and starts over again. Why is 6 volts from AA batteries not the same as 6 volts from the disk batteries?

    The current available from a couple of coin cells isn't the same as from some AA's.
    Just as a battery pack of 6 AA's can deliver a lot more than a 9V "transistor" battery.

    PE - If you took 4 3V coin cells, you wouldn't expect that would be enough to start the car with, would you?
  • MarkCrCoMarkCrCo Posts: 89
    edited 2014-04-25 06:45
    Sorry for the stupid question but can you explain more about the current vs voltage without having to write a whole book.
  • PJAllenPJAllen Banned Posts: 5,065
    edited 2014-04-25 06:52
    Knowing nothing of chemistry, cell density and so on, I think that you can appreciate, "intuitively", the difference/s given the examples previous.

    Here's a "book" -- http://web.mit.edu/evt/summary_battery_specifications.pdf
  • Beau SchwabeBeau Schwabe Posts: 6,566
    edited 2014-04-25 07:02
    Using an analogy, Voltage is potential and Current is force. Imagine dropping a bowling ball from a 10 story building versus dropping a BB from the same 10 story building. They Both have the same potential in that they have the same height and that they will fall at the same rate, however the bowling ball will have more "current" or force when it hits the ground than the BB will.
  • MarkCrCoMarkCrCo Posts: 89
    edited 2014-04-25 07:04
    I don't understand the current. If the current is dependent on the voltage and the resistance it seems the current should be the same if the voltage and the resistance in the circuit are the same. Obviously this isn't the case. Are they referring to the internal resistance with in the battery and not the resistance in the circuit?
  • TCTC Posts: 1,019
    edited 2014-04-25 07:04
    MarkCrCo wrote: »
    Sorry for the stupid question but can you explain more about the current vs voltage without having to write a whole book.

    I can give you an example. I know others on here can give a better one.

    Lets say you have a little kiddy pool( your boe-bot). And you want to fill that pool fast. So you grab the hose, turn on the water, and start filling it. Now you have water coming out of the hose (the battery voltage), but the water is not coming out fast enough. So you open the valve more (add more current) to fill the pool up faster.

    Yes, your boe-bot has the voltage (water in the hose), but you don't have enough current (amount of water) to drive the motors.

    Hope that helped.
  • TubularTubular Posts: 4,703
    edited 2014-04-25 07:06
    The coin cells have a much higher internal resistance than the AA cells. As the current increases, the voltage available to your circuit drops by that voltage drop across the internal resistance.

    If a CR2032 coin cell has an unloaded voltage of 3 volts and an internal resistance of 20 ohms, and you try and draw 100mA from it, the available voltage (at the coin cell terminals) will drop to something like 1 volt, causing a drop out and reset.

    Motors take a heap of current when they "lurch forward"
  • Mike GreenMike Green Posts: 23,101
    edited 2014-04-25 07:08
    Another good analogy is that of a stream of water. The amount of water flowing through a hose is the current. The pressure of the water is the voltage. A coin cell might be like a tall glass of water with a small hole at the bottom. A AA battery might be like a 5 gallon bucket the same height as the glass with the same size hole at the bottom. They both create the same strength stream of water with the same flow and force, but the glass runs out way faster than the bucket.
  • MarkCrCoMarkCrCo Posts: 89
    edited 2014-04-25 07:14
    Ok I'm trying to lighten his load and the AAs are heavy in comparison. If I were to wire in two more coin batteries in parallel would that give me more current -- poke two holes in the bucket instead of one?
  • MarkCrCoMarkCrCo Posts: 89
    edited 2014-04-25 07:24
    Assuming that my last post is correct... How do I know the current of the battery? Will I need a million parallel wired coin batteries to equal the current of the AAs or just 4?
  • Mike GreenMike Green Posts: 23,101
    edited 2014-04-25 08:38
    As Tubular mentioned, batteries have an internal resistance that limits the amount of current they can supply. Servo motors typically draw 1A or so for a short period of time when they start moving and coin cells maybe can supply 1/100 of that on a good day. Batteries, like other electronics parts, have datasheets and that will tell you how much current you can draw, both instantaneously and over time. The overall capacity of a battery (the size of the bucket) is given in AH (Ampere hours) or mAH (milliAmpere hours). The datasheet should also give you the internal resistance. Most batteries will have a lower capacity at high current loads than at low current loads and the datasheet should have a graph or chart that shows capacity vs current load.

    Here's the datasheet for AA cells.

    Here's a corresponding datasheet for a CR2032 coin cell.

    Note that a CR2032 is intended to provide maybe 10mA over a period of hours in short pulses, maybe a few seconds at a time. You might look at using two CR123A Lithium cells in a battery holder to get 6V at the sort of current you need. The Parallax penguin-bot used this for power. If you look around, you should be able to find them relatively cheaply.

    Here's the datasheet for the CR123A.
  • Duane DegnDuane Degn Posts: 10,588
    edited 2014-04-25 08:52
    To lighten the load you could use a different battery chemistry. Lithium Polymer (LiPo) batteries have a higher energy density. LiPo require special chargers and the voltage is different the batteries you're used to.

    You could use one LiPo cell (about 4V) and use a boost circuit to raise the voltage to 5V. Or you could use two (or more) LiPo cells in series and use a buck regulator to drop the voltage to 5V (or 6V depending on your needs/wants).
  • tonyp12tonyp12 Posts: 1,951
    edited 2014-04-25 09:10
    All Batteries are NOT the same, it's mostly the battery chemistry that make some battery having internal resistance that are higher than other types
    Those with high serial resistance can not supply current as much/fast as other battery-types can.
    If the power requirement are pretty high but very short, a large (low-ESR) capacitor can be your power-buffer. (ESR = Equivalent Series Resistance)

    Alkaline coin-cell batteries are like AA batteries, low resistance. But of course due to smaller size have a mAh that is much lower.
  • User NameUser Name Posts: 1,451
    edited 2014-04-25 13:06
    Speaking of chemistry, does CrCo refer to chromium cobalt?

    (FWIW, "User Name" == too-lazy-to-fill-in-the-box-with-something-clever)
  • TubularTubular Posts: 4,703
    edited 2014-04-25 13:30
    Have you considered AAA batteries? They're lighter. Or more exotic AAAA or 1/2 AA's?

    Otherwise you're going to have to take some current measurements. This might be a good idea. Work out how much current is being drawn, and choose a battery that can still supply enough voltage to keep the microcontroller alive under those load conditions.
  • LoopyBytelooseLoopyByteloose Posts: 12,537
    edited 2014-04-25 13:45
    gawd what a geeky bunch of ramble.

    It is quite simple. In terms of POWER. amps x volts = Watts, which is the measure of power.

    Volts alone is not a measure of POWER. Those tiny CrCo cells don't have enought amps in them to deliver more than a tweek to the BOEbot, and then reset.

    Right voltage, but size does matter. Bigger cells in general have more POWER. If you want to drive a robot, anything smaller than AAA cells are going to likely not work out.... unless you are very sure of matching the demands for power with the battery size.

    When the BOEbot's motors try to roll, the battery just gets too much current drain and the voltage drops below the reset level.

    When you increased the Load (the demand on power) beyond what the battery can deliver at a steady rate current, the voltage drops.. somewhat like a short circuit.
  • LoopyBytelooseLoopyByteloose Posts: 12,537
    edited 2014-04-26 06:12
    MarkCrCo wrote: »
    I don't understand the current. If the current is dependent on the voltage and the resistance it seems the current should be the same if the voltage and the resistance in the circuit are the same. Obviously this isn't the case. Are they referring to the internal resistance with in the battery and not the resistance in the circuit?

    I think it is very normal for the average person to thing Voltage is the equivalent of Power, but it is certainly not that. P = V X I

    As far as dependendencies, without current you don't have an electrical flow. We see static electric potentials of tens of thousand of volts, but not flow.
    And without resistance, the current approaches infinite as the voltage drops toward zero (this is a short circuit scenario)

    A POWER supply is a balance between adequate current flow and a high enough voltage to overcome the resisance of the actual load. The higher the load, the less resistance and greater amount of current required to sustain a voltage.

    Batteries are limited electrical supplies, not like plugging int a wall socket. The smaller the battery, the less power it is likely to have (though we have been trying to get denser power in batteries by changing chemistry).

    Since batteries are limited electrical supplies, big loads with just cause them to drain very quickly. Those coin shaped batteries were never intended to provide a lot of power. They are intended for 'micro-power devices'; such as calculators or clocks or backup power for some forms of volitile memory.

    ++++++++++
    There is an issue here of misperceptions.
    A lot of people think that everything in electronics can get smaller and smaller. But if you want to drive more and more powerful devices (motors, machines, home automation, heating, ventialation), the microcontroller can be quite small. But the interface devices and their power supplies can be quite large. And in some cases, devices need cooling as they can get quite hot.

    We are making huge progress with MOSfets to get smaller and cooler running interfaces, but not everything can be tiny.
  • PJAllenPJAllen Banned Posts: 5,065
    edited 2014-04-26 07:43
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  • whiteoxewhiteoxe Posts: 794
    edited 2014-04-26 14:11
    my 2 cents.... love mike greens analogy of voltage and power, i thought of it like standing on land with a little stream on one side of me and a great river on the other, both flowing past me at the same voltage/speed, so though both water sources have same speed the river is going to have a lot more current and power.

    I only figued out a little while ago why some bigger power tools in Australia boasted in big writing 2400 WATTS.
    our mains voltage is 240 and the current is 10 amps, 10 X 240 = 2400

    I always scew my face up when i hear on TV how the police had to use 50,000 volts to stop a suspect,first its unpleasant to hear of someone getting hurt but second, to me the 50,000 Volts is meaningless. i got zapped with a few hundred thousand volts on purpose in science class at school and it didnt hurt me at all!!! almost zero amps. This might be something along the lines loopy was mentioning ....static potential of tens of thousands of volts? I don't remember how the school experiment went, but i *think* it was actually a million volts I was hit with.!

    how many amps does a Taser have, and how do they get so many volts out of a small battery ?
  • PJAllenPJAllen Banned Posts: 5,065
    edited 2014-04-26 15:32
    whiteoxe wrote: »
    how do they get so many volts out of a small battery ?

    basically with an oscillator and voltage multiplication
  • whiteoxewhiteoxe Posts: 794
    edited 2014-04-26 15:48
    Think its time to go back to Jaycar :)
  • kwinnkwinn Posts: 8,697
    edited 2014-04-26 21:24
    AFAIK the taser produces a very brief pulse of current in the low mA range. They get such a high voltage by using a circuit similar to the CD ignition in a car. On a smaller scale of course.
  • LoopyBytelooseLoopyByteloose Posts: 12,537
    edited 2014-04-27 04:52
    Power calculations tend to be entirely ignored by those new to electricty...... until something dramatically burns up.

    In other words, while one might think you know everything because you can apply Ohm's Law; one must investigate the amount of power to assure safety and durabilty.

    In this case, not understanding Watts resulted in brown out, but the other option is a fireball.
  • PJAllenPJAllen Banned Posts: 5,065
    edited 2014-04-27 08:42
    Power calculations tend to be entirely ignored by those new to electricty...... until something dramatically burns up.

    In other words, while one might think you know everything because you can apply Ohm's Law; one must investigate the amount of power to assure safety and durabilty.

    In this can, not understanding Watts resulted in brown out, but the other option is a fireball.

    Yes, quite.
    Go sleep it off.
  • MarkCrCoMarkCrCo Posts: 89
    edited 2014-04-28 20:12
    Actually it was my old business name === Creative Computing
  • User NameUser Name Posts: 1,451
    edited 2014-04-28 21:01
    Ah, the mystery is solved...and as usual with an answer that makes a lot more sense than my fevered conjectures.

    Anyhow... Welcome, Mark from Creative Computing!
  • MarkCrCoMarkCrCo Posts: 89
    edited 2014-04-29 10:36
    Vacume.jpg
    Ok so I want to put my little robot to work vacuming the floors.Do you think this crude design will work?
    463 x 590 - 30K
  • kwinnkwinn Posts: 8,697
    edited 2014-04-29 12:04
    Not very well. The dirt will accumulate at the bottom of the filter where the exit hole is unless you raise the filter a bit on some screen. Another concern will be sealing around the outside of the filter. Might work better if the filter was fastened around the outside of a tube and the tube and filter then placed in a can.
  • MarkCrCoMarkCrCo Posts: 89
    edited 2014-04-29 18:24
    Ok so thinking about using a 2 liter pop bottle instead of the can and duct taping the filter to the inside edges. Thinking about placing it so the filter will be about an inch or so from the exit. Maybe even tape two halves of two seperate bottles together to give me the inputs and outouts for the air flow.
  • kwinnkwinn Posts: 8,697
    edited 2014-04-29 20:21
    Two bottles would be a step in the right direction, but you also have to take into account the filter you want to use. It is not a U shaped bag as your sketch shows, it is actually a round piece of filter paper with a flat center and the outer part bent up to form the pleated sides. That is not going to be easy to seal well.

    Since the filter is a flat circle perhaps it would be better to work with that by cutting 2 short (~1-2") sections of pipe with a diameter just a bit smaller than the diameter of the filter and clamp the filter between them. Seal the top and bottom with a flat sheet of plastic and use one section for the inlet, and the other for the exhaust. Makes the robot short for stability and access under furniture, and round for ease of maneuvering.
    MarkCrCo wrote: »
    Ok so thinking about using a 2 liter pop bottle instead of the can and duct taping the filter to the inside edges. Thinking about placing it so the filter will be about an inch or so from the exit. Maybe even tape two halves of two seperate bottles together to give me the inputs and outouts for the air flow.
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