How do I handle this division equation on the Propeller?

Don M

Lets say I have a counter counting up seconds. When I'm ready to display the elapsed time I want to display anything over 60 seconds as minutes & seconds.

So if I have a total seconds of say 125. So lets assign a long variable named time that adds up all the seconds.

time := time + seconds     ' time = 125

minutes := time / 60         ' answer is 2.083

So I know that minutes = 2 since the Prop doesn't deal with less than whole numbers but how do I get the .083 to convert back into seconds?

Thanks.
Don

Mike Green

Actually, the division operator does integer division, so the answer is 2, not 2.083. There's a corresponding remainder operation, "//" and "125 // 60" is 5 which is exactly what you want.

Phil Pilgrim (PhiPi)

Look up the modulus operator // in the Spin reference.

-Phil

JonnyMac

This is where the modulus (remainder of a division) operator is your friend. I'm coding a laser-tag application that has no spare cogs, so I synthesize the game timer in the main loop like this:

t1 := cnt
  repeat

    ' loop code

    t2 := cnt
    elapsedtix += t2 - t1
    if (elapsedtix => CLK_FREQ)
      gametimer += elapsedtix / CLK_FREQ
      elapsedtix //= CLK_FREQ
    t1 := t2

I convert seconds to HH:MM:SS format like this:

pub show_time(s) | h, m

'' Display timer as HH:MM:SS
'' -- time passed in seconds

  h := s  / 3600
  m := s // 3600 / 60
  s := s // 60

  dec2(h)
  term.tx(":")
  dec2(m)
  term.tx(":")
  dec2(s)

Don M

Thanks gentleman. Exactly what I needed.