Format question

Don M

I have a buffer: buffer[17]

In that buffer is the following characters: "-> 646E6C00BC3D"

I want to eliminate the "-> " and print the characters from the buffer to look like this by inserting a ":" every 2 characters: 64:6E:6C:00:BC:3D

So here is my code (that doesn't work right):

repeat i from 3 to 16
    term.tx(byte[@buffer][i])
    term.tx(":") 

How do I get it to print the ":" every 2 characters instead of every character?

Thanks.
Don

Don M

I made this work but is there a simpler way?

repeat i from 3 to 16
    term.tx(byte[@buffer][i])
    case i
      5, 7, 9, 11, 13:
        term.tx(":")

Mike G

Insert a modulus statement inside the repeat to check for an even or odd count.

IF i // 2 == 1
  term.tx(":")

Duane Degn

Don M wrote: »

I have a buffer: buffer[17]

In that buffer is the following characters: "-> 646E6C00BC3D"

I want to eliminate the "-> " and print the characters from the buffer to look like this by inserting a ":" every 2 characters: 64:6E:6C:00:BC:3D

So here is my code (that doesn't work right):

repeat i from 3 to 16
    term.tx(byte[@buffer][i])
    term.tx(":") 

How do I get it to print the ":" every 2 characters instead of every character?

Thanks.
Don

You want to print two characters between colons not one.

There are several ways to do this, here's one.

i := 3
repeat
    term.tx(byte[@buffer][i++])
    term.tx(byte[@buffer][i++])
    if i < 15
      term.tx(":") 
while i < 16

Edit: I see Mike G has another way.
Edit again: I hadn't seen post #2. There are sure a lot of ways to Spin a cat.

Don M

Thanks Mike & Duane!

JonnyMac

This is similar to what you're doing:

repeat ch from 3 to 14
    if (lookdown(ch: 5, 7, 9, 11, 13))
      term.tx(":")
    term.tx(byte[@buffer][ch])

This is longer, but might be easier to adapt as you can set the offset once, and number of byte pairs minus one at the top of the code.

p_buf := @buffer + 3

  repeat 5
    repeat 2
      term.tx(byte[p_buf++])
    term.tx(":")
  repeat 2
    term.tx(byte[p_buf++])