High power MOSFET question
I'm planning to make a brushless DC motor driver out of the prop. The motor I intend to drive has a 150A maximum current, and 60V maximum drive voltage. I plan to make a 3-phase driver with three SiR882DP mosfets per leg per phase; That's 18 MOSFETs per motor. I plan to use an integrated half-bridge gate driver IC, but I'm not sure how much gate drive current I need.
According to the SiR882DP datasheet, with a 4.5v gate voltage, it has a worst-case gate charge of 27nC. If I'm driving the bridges via differential DUTY mode on the counter, and I want to switch the MOSFET within 1/2 clock, then it seems I need 27nC*160Mhz=4.3Amps gate drive Per MOSFET. Am I going way overboard on this? Did I do some of my math wrong?
According to the SiR882DP datasheet, with a 4.5v gate voltage, it has a worst-case gate charge of 27nC. If I'm driving the bridges via differential DUTY mode on the counter, and I want to switch the MOSFET within 1/2 clock, then it seems I need 27nC*160Mhz=4.3Amps gate drive Per MOSFET. Am I going way overboard on this? Did I do some of my math wrong?
Comments
-Phil
-Phil
-Phil
On another topic of current flow, I've found inductors usable to 84 amps. Can I stack two on opposite sides of the board as long as I wire them in phase? If the bobbins stack in line, will I keep the inductor's rating and double the saturation current, or will the inductor value be halved?
The math is correct, and gate drivers of multiple peak-amps are easily available.
I'd say your assumption of needing to drive this in ~6ns is a little over-cooked though.
Your operating PWM frequency will be much lower, and slower FET edges are often chosen for better EMC.
So long as tr ~ tf, your drive delays do not greatly affect duty cycle.
Another reality check, 150A is not easy to manage on PCBs. If you take a nominal 10 milliohm sheet/path resistance, you get 225 watts of loss.
That's one fried assembly
Even your 0.5mOhm sense resistor, is 11 watts.
The 2KW RF generators of the ICP's I service use 2 sets of 4 fets to generate 1200 Watts required for the plasma, and the mismatch in load sharing is the greatest weakness of the design. As the components age the some transistors will carry less of the load and others more. Eventually this leads to a cascade failure.
So I'll be trying to keep the resistance under .25milliohm. The intent was one resistor per MOSFET, so 50A max per resistor. Since they're 2W resistors, and 150A is only a peak value, I think I'm okay.
150A is certainly a peak value. The motor, I think has ~10AWG or 8AWG wires going into it, so I don't plan on spending too much time at 150A. So, with 2oz copper, I need a trace 60cm (not 60mm) wide? I am sure that width is unnecessary since I've seen computer power supplies capable of 50A on the 12V rail, and they're less than 20cm wide in total, not to mention that I've seen PSUs good to 120A, so I know that can't be right. Finally, I've seen PCBs designed to take 10-20A and the traces aren't more than a few mm wide, and it didn't seem like even 2oz copper.
Should I build the output portion of this circuit out of buss bar? The MOSFETs are made to put heat into the PCB, not to an external heat sink, yet they're rated at 53W power dissipation at 70C.
My plan was to put one current-sense resistor on each transistor. It wouldn't be too hard to check the balance between the resistors in addition to adding them.
The 42.4 sq mm recommendation is the wire size for conductors carrying 150 amps continuously so it would be overkill for a brief peak current over a short path. You do however need to size the traces for the continuous current the motor draws at full load.
Components dissipating that kind of power have a tendency to turn PCB's into charcoal after a while so it would be a good idea to have something to dissipate the heat as rapidly as possible. True, the maximum rating is 53W at 70C, but the trick is keeping them at 70C when they are dissipating 53W. Mounting the output portion on a buss bar would certainly help with that. Fortunately if you can drive the gate hard enough to get the Rds on down to the .0073 ohms in the data sheet you will be under 20 watts dissipation at 50 amps current.
That will help a little with the load balancing but the Rds on of the transistor is approximately 15 times greater than that. From the data sheet the typical/max Rds on at 20A is 0.0071/0.0087 ohms. If that is extrapolated to 2 parallel transistors with 0.0005 ohm sense resistors providing 100A current the currents through the individual transistors would be approximately 55A for transistor 1 and 45A for transistor 2. Not a big difference, but one that must be taken in to account when operating close to the maximum ratings.