Can clkfreq be converted to float?

lardom

I want to use a float number in a 'delay' expression. The following line does not work;

waitcnt(clkfreq /(float) + cnt)

Calculating the distance along a circumference, C = 2pi * r, is easily done in the float objects. I want to be able to define speed as well as distance in float.

Bobb Fwed

You'll have to use a float conversion method from an object (like F32 or FloatMath), then do the float math, then convert it back to int.

So something like this:

waitcnt(FLT.FRound(FLT.FDiv(FLT.FFloat(clkfreq), [float val])) + cnt)

Duane Degn

Larry,

Like Bobb said, you could use a foating point conversion object to do this.

I think it would be best to wait to convert the difference of two times. Use interger math to do the subtraction of the two clock values and then, if you need/want to, convert this smaller number to a float. I bet just converting the final difference will save you a lot of headache.

lardom

Bobb Fwed and Duane Degn, thanks for your replies. I'm going to test your examples.
I think I spotted an important key in this thread. Here
Since the system counter only works with integers I see that I'll have to convert my result values to integers before I insert them into a waitcnt expression. I'll move the decimal points to the right to maintain precision and try again.

Bobb Fwed

That's what the FRound method does (I used that in my example).

lardom

Bobb and Duane, thanks a lot. I made great progress with my code. I met my short goal which was to write an object ahead of the motors and wheels that are being shipped to me.