Math Question
LisaQ
Posts: 33
Brushing upon some long forgotten math and came across something I don't understand. The question is how does 8 times the square root of (81- (216/32) ^2) simplify to 18 times the square root of 7? This is from this link:
http://www.khanacademy.org/video/part-1-of-proof-of-heron-s-formula.
Sadly, I've spent about 3 hours manipulating numbers and trying to work it out. Any help is appreciated.
http://www.khanacademy.org/video/part-1-of-proof-of-heron-s-formula.
Sadly, I've spent about 3 hours manipulating numbers and trying to work it out. Any help is appreciated.
Comments
If you don't get the right answer, its likely due to not doing the calcs within the brackets correctly. Divide 216/32 first. Square that answer. subtract from 81. Take the sq.root. Mult by 8. Same as 18 times sq. rt of 7.
The video actually goes through it quite well.
I think you misunderstood, I can get the answer on the calculator. 216/32 is equal to 6.75. Then square that to get 45.5625. Next subtract that from 81 to get 35.4375. The sqrt of 35.4375 is 5.95294...multiplied by 8 is 47.6235
What I am trying to figure out is how to do the problem in radical form, how to get the answer 18sqrt7- not the result of 18 multiplied by sqrt7.
Thanks,
Lisa
remember
(A^2)*(B^2)=(A*B)^2
Edit:
the attached file was extremely small.
I tried to make it bigger.
Thank you, that was exactly what I was asking for! Thank you everyone for your help.
Lisa
There's something fun about a really messy algebra problem.
Duane