Yes. Whenever a cog exits, it performs a stop instruction which turns off the cog's clock and clears the cog's I/O registers which sets the I/O mode of its I/O pins to input. Remember that if another cog is using the I/O pins as outputs, that takes precedence.
Comments
Simply end your program with a 'repeat' and you will loop forever.
that did the trick... dose that mean the chip goes to sleep if it is
not executing a program? turns off all it's ports..?
Bill