Active pull-up circuit? MCP42010
W9GFO
Posts: 4,010
What is an "active pull-up circuit" and how could it be floating if it is actively pulled up?
This is for the Reset and Shutdown pins on a MCP42010 digital pot. Since I'm not supposed to leave them floating can I just connect them directly to VDD or is a resistor necessary? The reset or shutdown occurs when they are pulled low, and I do not need that to happen.
Rich H
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The Simple Servo Tester, a kit from Gadget Gangster.
This is for the Reset and Shutdown pins on a MCP42010 digital pot. Since I'm not supposed to leave them floating can I just connect them directly to VDD or is a resistor necessary? The reset or shutdown occurs when they are pulled low, and I do not need that to happen.
MicroChip said...
In order to minimize power consumption, this pin
has an active pull-up circuit. The performance of this
circuit is shown in Figure 2-12. This pin will draw negligible
current at logic level ‘0’ and logic level ‘1’. Do not
leave this pin floating.
Rich H
▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔
The Simple Servo Tester, a kit from Gadget Gangster.
Comments
The external signal that controls the chip needs to hold these pins either high or low to minimize power consumption. If that external circuit is always active when power is on then no pullup or other connection is required.
Post Edited (kwinn) : 5/12/2010 4:42:20 PM GMT
Would I need a resistor on these pins or is it okay to connect them directly to 5V?
Rich H
▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔
The Simple Servo Tester, a kit from Gadget Gangster.
-Phil
Okay good. I wanted to make sure because I understand that current limiting resistors are mandatory for the base of a transistor.
Thanks,
Rich H
▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔
The Simple Servo Tester, a kit from Gadget Gangster.
-Phil