Help with SMS - Specified digit of number

Robert K

I am tryling to use Basic Stamp to send SMS. Cell phones normaly accept PDU format, so I need to convert data to PDU. Please look at program below. The problem that I have is: putting·digits ·directly into the program - everything is working great, when I am trying to take a number and use specified digits, I am getting some non-sens.

I am sure solution , like always is rather easy, but for some reason I can not see that. Please help ;

Thanks

Robert

PDU·· VAR Byte(7)
CH··· VAR Byte(8)
Value VAR Word


Value = 1234

CH(0)=Value DIG 3
CH(1)=Value DIG 2
CH(2)=Value DIG 1
CH(3)=Value DIG 0
CH(4)="5"
CH(5)="6"
CH(6)="7"
CH(7)="8"
' PDU shift routine
PDU(0)=(CH(1) << 7)+(CH(0) >> 0)
PDU(1)=(CH(2) << 6)+(CH(1) >> 1)
PDU(2)=(CH(3) << 5)+(CH(2) >> 2)
PDU(3)=(CH(4) << 4)+(CH(3) >> 3)
PDU(4)=(CH(5) << 3)+(CH(4) >> 4)
PDU(5)=(CH(6) << 2)+(CH(5) >> 5)
PDU(6)=(CH(7) << 1)+(CH(6) >> 6)
'PDU OUTPUT (should be :· 31 D9 8C 56 B3 DD 70
DEBUG HEX2 PDU(0),HEX2 PDU(1),HEX2 PDU(2),HEX2 PDU(3),HEX2 PDU(4),HEX2 PDU(5),HEX2 PDU(6),CR

Franklin

Robert K said...
when I am trying to take a number and use specified digits, I am getting some non-sens

What nonsense are you getting? The program is probably doing exactly what you are telling it to do, but you are telling it to do something other than what you want. Computers work that way.

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- Stephen

Robert K

I am getting :
01 C1 80 50 B3 DD 70
which after conversion back to text is :
£$¥è567

Should be :
31 D9 8C 56 B3 DD 70
which convert to (cottected values)
1234567
So first 4 numbers are translated wrong, the one that I left unchanged are ok

Mike Green

Value DIG 3

This gives you a value from 0 to 9, not an ANSI character.

Try: (Value DIG 3) + "0"

Robert K

Thanks that works !!!,
Robert