How to handle "cnt" overflows ?

DavidGreg

Is the following construct valid? Will it handle CNT overflow?

repeat
       counter1 := cnt + CLKFREQ/2
       doSomething()
       repeat until (cnt > counter1)
              counter2 := cnt + CLKFREQ/20
              doSomethingElse()
             waitcnt(counter2)

Post Edited By Moderator (Bean (Hitt Consulting)) : 11/18/2009 2:59:13 PM GMT

Phil Pilgrim (PhiPi)

No. To handle cnt overflow, you need to change your until clause to (cnt - counter1 > 0).

-Phil