Converting Binary to Hex

trytryagain

Peter,

First of all thanks for all the great information
I've read from your posts.

I am new to javelin stamp and I'm trying to convert some binary inputs to hex.

The Format.printf works great printing out to the debugger
but I need these values in my code.

Is there a method to store the hex info as a string and build it as it comes in?

while (fingerReceive.byteAvailable() == true)
{
b = (char)fingerReceive.receiveByte();
Format.printf("%x",b);
}

Thanks for taking a look at this

Jeff
·

Peter Verkaik

You·can use Format.sprintf() and Format.bprintf() to print
to a char[noparse]/noparse rather than System.out

regards peter
·

trytryagain

Thanks very much Pete

I am getting wacky results that differ from the original

with this code:

cIndex = 0;

while (fingerReceive.byteAvailable() == true)
{

b = (char)fingerReceive.receiveByte();

cIndex = Format.bprintf(cBuffer,cIndex,"%x",b);
String s = Integer.toString(cBuffer[noparse][[/noparse]cIndex]);
cIndex = cIndex + 1;
buffer.append(s);

}

System.out.println(buffer.toString());

Data seems to be getting lost with my method above.

Is there an easier loop to concat and show the entire string?

Thanks

Jeff


·

Peter Verkaik

cIndex = 0;
while (fingerReceive.byteAvailable() == true) {
  int b = fingerReceive.receiveByte();
  cIndex = Format.bprintf(cBuffer,cIndex,"%02x",b&0xFF);
}
cBuffer[noparse][[/noparse]cIndex] = 0; //add closing null
Format.printf("%s\n".cBuffer); //printf checks for closing null

regards peter

Post Edited (Peter Verkaik) : 9/22/2009 10:29:47 PM GMT