inexpensive CT rings
I have designed project to use 4-20ma current rings like this -www.automationdirect.com/adc/Shopping/Catalog/Sensors_-z-_Encoders/Current_Sensing_Transducers/AC_Current_Transducers
Anyways, why are they so expensive? These - www.greegoo.com/interface-operator-components/current-transformers-msq-30.htm are much less expensive, but they are current transformers. Is there a good way to use these, or does the proper circuitry cost $75 to emulate?
My circuitry now consist of a 24v supply through a 50ohm resistor, to the ring, and back to a 100ohm shunt resistor to ground.
Anyways, why are they so expensive? These - www.greegoo.com/interface-operator-components/current-transformers-msq-30.htm are much less expensive, but they are current transformers. Is there a good way to use these, or does the proper circuitry cost $75 to emulate?
My circuitry now consist of a 24v supply through a 50ohm resistor, to the ring, and back to a 100ohm shunt resistor to ground.
Comments
Rich H
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The Servo Boss, a 12 channel servo tester kit from Gadget Gangster.
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- Stephen
There are a few sources mentioned in this thread ..
http://forums.parallax.com/showthread.php?p=795321
Regards,
John Twomey
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'Necessity is the mother of invention'
'Those who can, do.Those who can’t, teach.'
'Convince a man against his will, he's of the same opinion still.'
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· -- Carl, nn5i@arrl.net
The transducer has all the hard work already done, is calibrated and safety certified for use on the bus voltage you need. Starting with a $3 CT, you'll quickly burn up the difference in price before you send the thing for safety certification.
One thing I'd suggest is always using a 5 amp to 4-20 mA transducer. That way, as the requirements change, you can feed it with any cheap current transformer, whether you need 1000:5, 100:5 or 10:5.
Cheers,
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Tom Sisk
http://www.siskconsult.com
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That is an interesting thought.
Thanks though, stamptrol, because I need a feel for what I am up against. I've found that many times you can be better off sticking with the apparently more expensive option.