74HC165 with two decimal Push swithces

Rino

The circuit with the 74HC165 shift register and the two decimal push switches works fine with the BS2.· I can read the·switch positions 0 to 9 each.· The 4 bits of each switch is combined into an 8 bit word when I read it with DEBUG.·· I want to get mumbers 0 to 99, I have to multiply this number with another number but when I set·the switches to 99, the number I·get·is 153.·· The ten switch gives me 16, 32 and so on.· I probably have to separate the 8 bit word and recombine it to get the number I need.·
Is there a better way to do it?

Beau Schwabe

In your DEBUG command, use the HEX descriptor before the value you want to display.

Decimal 153 equals 99 Hex.

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Beau Schwabe

IC Layout Engineer
Parallax, Inc.

Rino

That was a quick response!
Yes I get that but when I multiply it with another number, it is 153 that is used.

Thanks for the quick reply.

Rino

Beau Schwabe

Rino,

You need to convert your BCD Hex number into a Decimal number first before you can perform any math operations to it.

Here is an example:

' {$STAMP BS2}
' {$PBASIC 2.5}


Number  VAR Word
Temp    VAR Word

Number = 153

'Convert BCD Hex number into Decimal number
Temp.HIGHBYTE = Number / 16
Temp.LOWBYTE = Number - (Temp.HIGHBYTE * 16)
Temp.HIGHBYTE = Temp.HIGHBYTE * 10

Number = Temp.LOWBYTE + Temp.HIGHBYTE

MainLoop:
  DEBUG DEC Number,CR
  GOTO MainLoop

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Beau Schwabe

IC Layout Engineer
Parallax, Inc.

Rino

Thanks again.
I am going to try that.

Rino

Rino

It works just fine.
Thank you
Rino