Counting the number of numbers, in a number

grasshopper

I am trying to count how many numbers I have in a number. For example the number 1562 has 4 numbers the 1,5,6,2. I can do this using math and logic, but I wanted to know if there was any other way to achieve this preferably with out using any math or divide statements.

Thanks

Philldapill

If you don't want to do divide, you could always have a repeat loop and check if the number is less than...

X := 9 repeat i from 1 to 9
  if(number <= x)
    NumberOfDigits := i
    break  (or whatever spin equivalent is... I forgot)
  x := x * 10 + 9

I don't think there is a simple one-shot process for doing this, but I'm probably wrong... people on this forum amaze me with their tricks consistantly.

Lord Steve

The one-shot process to do this is to take the logarithm (in this case base-10) of the number and the integer part of the logarithm PLUS ONE gives you the number of digits in that base.· That is more complicated than divide, though.

StefanL38

hello grasshopper,

I think it can't be done within one line

if you don't want a loop

you could use a case-construction

case MyVariable
1..9
10..99
100...999

etc.

but I think the best way is the way like the method "DEC" in the FullDuplexSerial-object does it

Your asking for ONE detail. What is it good for ? If you describe your COMPLETE target there might be still other ways to achive it

best regards

Stefan

grasshopper

StefanL38

That might be what I am looking for. Currently I use a bit of math and have to float not float etc. Ill test this today. Thanks

RiJoRi

How about something like this:

Base := 10 ' or 2, 4, 8, 16, etc.
Digits := 0
Limit := 1
repeat while Limit =< Number
    x *= Base
    Digits++  ' count the number of Base digits in Number

I am at work, and my P'lax stuff is home, so I'm not too sure of the syntax. Also, I've done a sheet-of-paper check, and I BELIEVE the algorithm is good, but "buyer beware"!

--Rich

Chris Savage

The subject line threw me for a loop. Maybe number of digits in a number?

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Chris Savage
Parallax Engineering

DosManDan

Make it nice and easy, no math at all - This will do 4 digits (9999). I don't use Spin, so I don't know the exact coding of an IF statement for the Prop, but the logic below should be easy to code.

If X >= 1000 Then
· Count = 4
ElseIf X >= 100 Then
· Count = 3
ElseIf X >= 10 Then
· Count = 2
Else
· Count = 1 'Zero counts as one digit
End If

grasshopper

DosManDan, Yea this is sort of the way I went, but fitted it so that it could handle a negative and floating point number. Thanks all for the help