Reading the AD592 using the RC TIME command How would I do the Math for this Ce

sam_sam_sam · 2008-07-31 00:36

How can·I change the reading from degrees Kelvin to Fahrenheit

······· ·K]·=·([noparse][[/noparse]°F]·+·459.67)·×·⁵⁄₉

_{How would I do the Math for this}

Fahrenheit to Celsius C = (F - 32) x 5/9

Figure 2-9b Temperature Conversion Formulas Conversion Formula Example

Celsius to Kelvin K = C + 273 21 oc = 294·K^{Kelvin to Celsius C = K - 273 313 K = 40 oC

Fahrenheit to Celsius C = (F - 32) x 5/9 89 oF = 31.7 oC

Celsius to Fahrenheit F = (C x 9/5) + 32 50 oC = 122 oF}

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··Thanks for any·

·that you may have and all of your time finding them

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Sam

Post Edited (sam_sam_sam) : 7/31/2008 1:02:02 AM GMT

Zoot · 2008-07-31 01:02

Algebra:
K = ([noparse][[/noparse]°F] + 459.67) × (5⁄9)
K / ( 5/9 ) = F + 459.67
( K / ( 5/9 ) ) - 459.67 = F

Integer Math:
KelvinOffset CON 460 ' 459.67 from above
' 1 / (5/9) = 1.8
' 1.8 * 256 = 460.8
KelvinK CON 461 ' 460.8 from above
Faren VAR Word

Faren = K */ KelvinK - KelvinOffset

Then remember that if the result (Faren) ends up with BIT15 being set to 1, then the result (Faren) is a NEGATIVE number.

Also, I have no idea if that formula is ideal -- I bet others could weigh in w/more accurate conversions (see emesystems.com -- I bet Tracy Allen covers this, with more precise math)

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When the going gets weird, the weird turn pro. -- HST

1uffakind.com/robots/povBitMapBuilder.php
1uffakind.com/robots/resistorLadder.php

sam_sam_sam · 2008-07-31 03:32

Zoot

Thank You for your help with the math

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··Thanks for any·

·that you may have and all of your time finding them

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·
·
·
Sam

Reading the AD592 using the RC TIME command How would I do the Math for this Ce

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