Power Demands of Propeller
Philldapill
Posts: 1,283
I'm working on a small hobby wind turbine using a stepper motor. I have jillions of these stepper motors and like to tinker with them in many ways. I know using one of these as a generator doesn't output much power, but I don't care. I just like to play with the proof of concept, rather than the finished device. Anyway, I've got my makeshift stepper generator up and running, but it only outputs about 200mW into a 12.6V battery. Not much power. This is the problem actually. The open circuit voltage is something like 28V after the stepper output goes through a transformer. Apparently, this isn't enough current to "charge" the battery. It's a fairly good size battery out of a gate opener - not TOO big like a car battery, 7AH.
Anyway, here's where the propeller comes in. I need to know if there is anyway to reduce the power requirements of the prop significantly. I want to be able to use it to control the charging of the battery. If I just have the rectified output straight into the battery, it doesn't charge. I think this is due to the tiny current not being enought to really CHARGE it. Instead, I want to use the propeller to control a circuit to have the generator charge up a fairly large cap bank, then discharge that bank into the battery, thereby REALLY increasing the current into the battery, but reducing duty cycle tremendously. I'm not sure if this would aid in actually charging the battery or not. In addition to this problem, if I use a simple passive circuit to feed current into the battery ALL the time, there are hardly any loses, except for the bridge rectifier. If I use the propeller in addition to that, I'm sure it will consume a good bit of my 200mW. Any ideas on how to get more bang for the buck?
Anyway, here's where the propeller comes in. I need to know if there is anyway to reduce the power requirements of the prop significantly. I want to be able to use it to control the charging of the battery. If I just have the rectified output straight into the battery, it doesn't charge. I think this is due to the tiny current not being enought to really CHARGE it. Instead, I want to use the propeller to control a circuit to have the generator charge up a fairly large cap bank, then discharge that bank into the battery, thereby REALLY increasing the current into the battery, but reducing duty cycle tremendously. I'm not sure if this would aid in actually charging the battery or not. In addition to this problem, if I use a simple passive circuit to feed current into the battery ALL the time, there are hardly any loses, except for the bridge rectifier. If I use the propeller in addition to that, I'm sure it will consume a good bit of my 200mW. Any ideas on how to get more bang for the buck?
Comments
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Now, back to reality of the current way I'm doing it.... each time the stepper rotor passes a pole inside, it pushes a TINY bit of charge across the transformer, and to the battery... SLOW charge, but constant... I just figured there was a medium somehwere in the middle...
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Beau Schwabe
IC Layout Engineer
Parallax, Inc.
Perhaps if you have a jillion of these stepper motors, there's your solution! Fill your backyard with windmills!
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Absolutely right! - lol ... I was hinting that perhaps his current configuration my not be·optimal for getting the most out of the stepper/generator.
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Beau Schwabe
IC Layout Engineer
Parallax, Inc.
Now, in reality, I'm guessing there is another piece in play here - the self discharge of the battery itself. It only makes sense that the average power output from the generator would have to exceed the self discharge power dissipated by the battery. Correct?
Think I would take the highly variable output of the generator, run it thru a bridge rectifier and highly filter it with large capacitors allowing for long drain times during brownouts, and power a simple 555 timer chip to generate ac that I would run thru a transformer and convert to a dc level for charging.
its much easier to design and implement an over charge protection system dealing with battery voltage levels, verses trying to control your source voltages.
Also the 555 is very very cheap and operate over a wide voltage range...
nowdays the 555 in packs of 10 are dirty cheap...blow them up at will.
Post Edited (Burritoe) : 5/24/2008 10:00:34 PM GMT
I still think the best approach would be to get a jillion windmills going!
Theoretical time required to charge the battery with 200mW with no heat losses:
7AmpHours x 3600 seconds/hour x 12 volts = 302,400 Jules
302,400 J / 0.2W = 1,512,000 seconds = 420 Hours = 17.5 days (at 100% efficiency).
I'm guessing if you get about 30 windmills going, you should be able to charge your battery in less than a day with a good stiff breeze.
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Energy stored on Cap = 0.5 * C * V * V = 302400 Joules
for a 12V charge: C = 4200 F·!!· Quite a big capacitor!
Note also that·the turbines would need to supply twice the energy·stored on the cap, see:
http://hyperphysics.phy-astr.gsu.edu/hbasees/electric/capeng2.html#c1