Feeding an external pulse, or pulses, to one of the pins on a BS2, what is maxi
Using a 2 transistor MV (flip-flop) that·outputs 9.0v pulses, I figure that a voltage divider should be used to reduce pulse volts by half.··Would that·be OK?·· Should voltage-divider resistances be large? 110K,·for instance? I don't know what the input impedence of the BS2 pins are·
Comments
Half of 9V is 4.5V which is a perfectly good logic high voltage (2V is minimum logic high).
A 1uA leakage current is roughly 5 Megs, so the voltage divider resistances can certainly be on the order of 100K.
The 22 Kohm resistor is needed to limit the amount of current that the protection diodes have to deal with. They can't deal with much -- look at the Microchip documentation for the 16C57 I/O pins to see how much exactly -- but 22 Kohm should deal with a -12 to +12 volt signal. Your zero to 9 volt signal is in that range.
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Chris Savage
Parallax Tech Support
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Chris Savage
Parallax Tech Support