wz/if_z not doing what I expect
SSteve
Posts: 808
Given this code:
The line that begins with "if_z" shouldn't execute, right? When I run the code, it does. The complete program is attached. if I replace "test_value" in the excerpt above with "#1", the line that begins with "if_z" (as expected) doesn't execute.
What I think is happening is that the mov statement above moves the value $FFFF_FFFF into test_reg. Where am I going wrong?
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OS-X: because making Unix user-friendly was easier than debugging Windows
DAT
...
mov test_reg, test_value wz
if_z mov wait_time, long_wait_time
...
long_wait_time long $C000000
short_wait_time long $A00000
wait_time res 4
wait_reg res 4
test_value long $FFFF_FFFF
test_reg res 4
The line that begins with "if_z" shouldn't execute, right? When I run the code, it does. The complete program is attached. if I replace "test_value" in the excerpt above with "#1", the line that begins with "if_z" (as expected) doesn't execute.
What I think is happening is that the mov statement above moves the value $FFFF_FFFF into test_reg. Where am I going wrong?
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OS-X: because making Unix user-friendly was easier than debugging Windows
Comments
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Who says you have to have knowledge to use it?
I've killed a fly with my bare mind.
· I had made the same mistake, and couldn't figure it out either.
· Look through the "Tricks & Traps" document, it has alot of good info.
Bean.
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OS-X: because making Unix user-friendly was easier than debugging Windows