wz/if_z not doing what I expect

SSteve · June 2006

Given this code:

DAT
              ...

              mov test_reg, test_value          wz
        if_z  mov wait_time, long_wait_time

              ...

long_wait_time          long    $C000000
short_wait_time         long    $A00000
wait_time               res     4    
wait_reg                res     4
test_value              long    $FFFF_FFFF
test_reg                res     4

The line that begins with "if_z" shouldn't execute, right? When I run the code, it does. The complete program is attached. if I replace "test_value" in the excerpt above with "#1", the line that begins with "if_z" (as expected) doesn't execute.

What I think is happening is that the mov statement above moves the value $FFFF_FFFF into test_reg. Where am I going wrong?

▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔
OS-X: because making Unix user-friendly was easier than debugging Windows

CJ · June 2006

all of the predefined data, needs to be before the reserved space, the modified code is attached

▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔
Who says you have to have knowledge to use it?

I've killed a fly with my bare mind.

Bean · June 2006

Steve,
· I had made the same mistake, and couldn't figure it out either.
· Look through the "Tricks & Traps" document, it has alot of good info.
Bean.

▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔
Cheap 4-digit LED display with driver IC·www.hc4led.com

COMING SOON "SD DATA LOGGER" www.sddatalogger.com

"I reject your reality, and substitute my own." Mythbusters
·

SSteve · June 2006

Thanks, CJ & Bean. I don't know how I managed to miss the Tricks & Traps document. I guess that was before I started reading the Propeller thread. What a life saver! I already managed to learn two of the Tricks the hard way.

▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔▔
OS-X: because making Unix user-friendly was easier than debugging Windows

Equip your Genius

Categories

wz/if_z not doing what I expect

Comments