A MOSFET might be a better choice here.· There are several examples on the forums here for using one, but basically you'll need the MOSFET and a resistor.· Unlike a transistor, this·resistor actually connects to ground.
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roboticmaggot said...
I need a transistor to hook to a basic stamp for turning on/off a 2 amp current load. The load is 75 superbright LEDs.
Any ideas?
Thanks!
We would need more info, ie;
What is the led max supply voltage? Which determines if some of the leds will be in series...
At 12V you could have 3 leds in series with a resistor for the proper current regulation...
It all depends on the specs of the led you are going to use, some bright white leds have a vf of 3.6 max at 30ma,
so 3 x 3.6v = 10.8v at 30 ma plus the proper resistor....
75 / 3 = 25 25 x .03 = .75 A or 750 ma
If you do it this way, your power requirements for the solid state switch (mosfet/transistor) will be a lot lower.
roboticmaggot said...
I am running the LEDs in series sets of 4 with a 12v supply.
What about an IRL520N?
What is the max current of the leds????
75 / 4 = 18.75 or
19 strings of 4 each, for a total of 76 leds...
25 strings of 3 each, for a total of 75 leds...
19 x 25 ma = 475 ma
25 x 25 ma = 625 ma
Also, you would be much safer to put a resistor on each string of leds, as it would be much safer, and the resistor
would NOT have to handle such a large load...
Plus each led is not always the same as the next as far as light output, quality..... You will have to match em to get
an equal output....
Dont forget the ULN2003 chips!!! They can handle high voltage, and high current. You can drive your 12volts at 2 ampere with a single ULN2003 chip set up so the lines are parallel.
kenm said...
the irl device is specifically designed to turn on fully with a logic level voltage (and the stamp 5v does the job nicely), hence the l in irl.
The irf on the other hand will switch only about 2 amps at 5 volts to the gate. To switch higher currents more than 5 volts is needed.
Kramer said...
I suspect that you are going to smoke that UNL2003 by trying to drive 2 amps.
Take a look at the total power output for the package. I think it is 500milliwatts
From the DATASHEET.
The ULN2001A, ULN2002A, ULN2003 and
ULN2004A are high voltage, high current darlington
arrays each containing seven open collector darlington
pairs with common emitters. Each channel
rated at 500mA and can withstand peak currents of
600mA. Suppression diodes are included for inductive
load driving and the inputs are pinned opposite
the outputs to simplify board layout.d
Combine all 7 channels and you have over 3.5 ampere.
Natually a DIP package supplying 3.5 ampere WOULD NEED A HEAT SINK.
But I do not know if this person requires continual supply of power, or a low duty cycle.
Also I have NOT tried it myself so I cannot say for certain that the DIP package can withstand this kind of power.
The data sheet suggests it can, when its within its thermal limits...
If sustained ampere is required, most likely a transistor is better, as it is made to withstand MUCH higher thermal limts.
Plus who wants to put a heatsink on a DIP.. I dont even know how one would go about it.
If you know you'll need a heat sink on a chip, try your best to find a ceramic packaged chip instead of plastic, it has better heat conduction and can withstand higher temperatures. Most "need to sink" components have means for heat conduction through the ground pins the TO-220 package is a good example but there are several other packages that do it via wider center pins for ground.
Comments
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Chris Savage
Parallax Tech Support
csavage@parallax.com
We would need more info, ie;
What is the led max supply voltage? Which determines if some of the leds will be in series...
At 12V you could have 3 leds in series with a resistor for the proper current regulation...
It all depends on the specs of the led you are going to use, some bright white leds have a vf of 3.6 max at 30ma,
so 3 x 3.6v = 10.8v at 30 ma plus the proper resistor....
75 / 3 = 25 25 x .03 = .75 A or 750 ma
If you do it this way, your power requirements for the solid state switch (mosfet/transistor) will be a lot lower.
A power mosfet is the best way to go....
Bob N9LVU
What about an IRL520N?
What is the max current of the leds????
75 / 4 = 18.75 or
19 strings of 4 each, for a total of 76 leds...
25 strings of 3 each, for a total of 75 leds...
19 x 25 ma = 475 ma
25 x 25 ma = 625 ma
Also, you would be much safer to put a resistor on each string of leds, as it would be much safer, and the resistor
would NOT have to handle such a large load...
Plus each led is not always the same as the next as far as light output, quality..... You will have to match em to get
an equal output....
Bob N9LVU
19 strings of 4 each, for a total of 76 leds...
Ken
is there any real difference between an IRF520 and an IRL520?
The IRF on the other hand will switch only about 2 3 amps at 5 volts to the gate. To switch higher currents more than 5 volts is needed.
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Ken
Post Edited (KenM) : 10/27/2005 2:31:26 PM GMT
Good luck.
Take a look at the total power output for the package.· I think it is 500milliwatts
Amps x Volts = watts··· 2ampsX12volts = 2400 milliwatts
And watts = heat· Heat = smoke and fire.· Hmmmm.
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"When all think alike, no one is thinking very much.' - Walter Lippmann (1889-1974)
······································································ Warm regards,····· G. Herzog [noparse][[/noparse]·黃鶴 ]·in Taiwan
thanks!!
From the DATASHEET.
The ULN2001A, ULN2002A, ULN2003 and
ULN2004A are high voltage, high current darlington
arrays each containing seven open collector darlington
pairs with common emitters. Each channel
rated at 500mA and can withstand peak currents of
600mA. Suppression diodes are included for inductive
load driving and the inputs are pinned opposite
the outputs to simplify board layout.d
Combine all 7 channels and you have over 3.5 ampere.
Natually a DIP package supplying 3.5 ampere WOULD NEED A HEAT SINK.
But I do not know if this person requires continual supply of power, or a low duty cycle.
Also I have NOT tried it myself so I cannot say for certain that the DIP package can withstand this kind of power.
The data sheet suggests it can, when its within its thermal limits...
If sustained ampere is required, most likely a transistor is better, as it is made to withstand MUCH higher thermal limts.
Plus who wants to put a heatsink on a DIP.. I dont even know how one would go about it.
Aavid-Thermalloy makes plenty of different heat sinks for DIP packages:
http://www.aavidthermalloy.com/cgi-bin/standarda.pl?PgNum=1&thermalresist=40.5&HeightMax=7&HeightMin=2&SortBy=TR&NumPerPage=all&Device=12&x=28&y=9
Regards,
Bruce Bates
LoL, just kiddin.. But wow, I guess now I know....
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Ken
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