Get individual characters from integer value

ryfitzger227 · 2018-12-17 09:08

Hello everyone. I feel like this should be simple, but I do not know how to do this in spin.

A value is being sent via a serial port in the following format: "B12345," (I'm using the Extended fullduplex serial so , is the delimiter.)

I am then taking everything after the first character and converting it to an integer. So the integer will equal 12345. I need to split this integer into 5 different variables equaling 1, 2, 3, 4, & 5. How do I go about this?

Here's my code:

PUB readSerial | type, content, contentAdr, value, b

  repeat

    readBuffer := "0"
    serial.rxflush
  
    repeat until readBuffer <> "0"
      serial.RxStr(@readBuffer)

    type := readBuffer 'Take first character of string sent from computer to see type
    content := readBuffer[1] 'Take everything after the first character to get content
    contentAdr := @readBuffer[1]

    if type == "A"
      if content == "1"
        winValue := 1
      elseif content == "2"
        winValue := 2
    
    if type == "B"

      value := 0                                                    ' reset value                                                   

        repeat
          b := byte[contentAdr++]                                           ' get digit from string
          if ((b => "0") and (b =< "9"))                              ' if digit
            value := value * 10 + (b - "0")                           '  update value
          else
            quit

      testVar := value
      
      if testVar == 12345
        serial.str(string("matches/"))
      else
        serial.str(string("not a match/"))

      update(@digit1, @digit2, @digit3, @digit4, @dp)

testVar is equaling 12345 so I know the conversion is working properly. I just need to get digit1, digit2, etc to equal 1, 2, 3, etc.

Thank you in advance.

yeti · 2018-12-17 11:58

You get a string like "31415", convert it by summing it digitwise times 10^n to an integer and then want to process individual digits?

Why not just subtract "0" (= 48) from all nonzero bytes in the string to get a string of 5 values of 0 to 9 and pass these bytes to your update function?

JonnyMac · 2018-12-18 01:52

Here's a little method that will convert a decimal string to a value. You need to capture your input and then pass a pointer (the address of using @) to the first digit in the string to this method. It will return when it hits a non-digit in the string (any delimiter).

pub dec_value(p_str) : value | c

  repeat
    c := byte[p_str++]
    if ((c => "0") and (c =< "9"))
      value *= 10
      value += (c - "0")
    else
      quit

MIchael_Michalski · 2018-12-18 19:42

begin loop
i=1
digit = string-48
value = 10*value + digit
loop until your at the last character of string[]

Ariba · 2018-12-19 00:00

Either you extract the digits from the received string:

  testVar := value

  digit1 := byte[contentAdr - 6] - "0"
  digit2 := byte[contentAdr - 5] - "0"
  digit3 := byte[contentAdr - 4] - "0"
  digit4 := byte[contentAdr - 3] - "0"
  digit5 := byte[contentAdr - 2] - "0"

or you calculate the digits from the decimal value, this is more universally usable:

  testVar := value

  digit1 := value / 10000 // 10
  digit2 := value / 1000 // 10
  digit3 := value / 100 // 10
  digit4 := value / 10 // 10
  digit5 := value / 1 // 10

Andy

ryfitzger227 · 2018-12-19 04:02

Andy,

Thank you so much.. This worked great.

Get individual characters from integer value

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