Question. If a program in main launches a cog and sends it pointers.
‘Start new cog and send long ptr @aptr @bptr
Long[a] := long[b]
If there a way to calculate the difference in time it could take to make a = b using the method above versus if the main program did the equation itself a:=b. And is the time difference affected based on the order of the cogs and if the sub is at some unknown cog number. I’m trying to see if this time difference can be determined at 80Mhz