I'm constructing an 8-bit VGA DAC (RRRGGGBB), and found this Stack Overflow answer going into some solid detail on implementation
If you look at the bottom of the answer (the "edit"), he makes the claim that...
"I believe you can see in the image above that you don't want 400 mV at the input of the other side of the transmission line. You want 200 mV there. The 75 Ω series termination resistance and the 75 Ω parallel termination resistance forms a voltage divider with a ratio of 2:1. So it will expect half the voltage, not the entire voltage."
I'm not quite understanding his logic here, and I'm not seeing how the correct voltages are reaching the monitor. Can anyone give me a clue?