scotta

01-30-2007, 09:53 AM

I have 5 numbers in 5 RES variables.

A1

A2

A3

A4

A5

How do I toss the high and low values, then average ?

A1

A2

A3

A4

A5

How do I toss the high and low values, then average ?

View Full Version : Assembly Averaging

scotta

01-30-2007, 09:53 AM

I have 5 numbers in 5 RES variables.

A1

A2

A3

A4

A5

How do I toss the high and low values, then average ?

A1

A2

A3

A4

A5

How do I toss the high and low values, then average ?

Mike Green

01-30-2007, 10:54 AM

Define new RES variables "MaxVal", "MinVal", and "Total" and do:

mov MaxVal,A1 ' This can be made into a loop with

mov MinVal,A1 ' any number of variables, but this

mov Total,A1 ' is simpler when only a few variables

add Total,A2 ' are used

min MaxVal,A2

max MinVal,A2

add Total,A3

min MaxVal,A3

max MinVal,A3

add Total,A4

min MaxVal,A4 ' Note that this wouldn't necessarily

max MinVal,A4 ' be what you want if two or more

add Total,A5 ' values were the high or low values

min MaxVal,A5

max MinVal,A5

sub Total,MaxVal ' Toss the high and low values

sub Total,MinVal ' and divide by 3 to get average

mov MaxVal,#3 ' Reuse MaxVal and MinVal since

shl MaxVal,#14 ' they're not needed further

mov MinVal,#16

:divide cmpsub Total,MaxVal wc

rcl Total,#1 ' See document called Propeller Guts

djnz MinVal,#:divide ' Result is left in "Total"

Post Edited (Mike Green) : 3/5/2007 6:49:02 PM GMT

mov MaxVal,A1 ' This can be made into a loop with

mov MinVal,A1 ' any number of variables, but this

mov Total,A1 ' is simpler when only a few variables

add Total,A2 ' are used

min MaxVal,A2

max MinVal,A2

add Total,A3

min MaxVal,A3

max MinVal,A3

add Total,A4

min MaxVal,A4 ' Note that this wouldn't necessarily

max MinVal,A4 ' be what you want if two or more

add Total,A5 ' values were the high or low values

min MaxVal,A5

max MinVal,A5

sub Total,MaxVal ' Toss the high and low values

sub Total,MinVal ' and divide by 3 to get average

mov MaxVal,#3 ' Reuse MaxVal and MinVal since

shl MaxVal,#14 ' they're not needed further

mov MinVal,#16

:divide cmpsub Total,MaxVal wc

rcl Total,#1 ' See document called Propeller Guts

djnz MinVal,#:divide ' Result is left in "Total"

Post Edited (Mike Green) : 3/5/2007 6:49:02 PM GMT

scotta

03-05-2007, 11:58 PM

Your brain sees problems differently than mine does. It takes me 10 minutes to read

something like this before it clicks.

Sorry I didn't get back to you on this sooner.

Thanks,

Scott

something like this before it clicks.

Sorry I didn't get back to you on this sooner.

Thanks,

Scott

Mike Green

03-06-2007, 12:23 AM

There are a couple of things going on there

1) Accumulating a total of the points

2) Determining the maximum of the points

3) Determining the minimum of the points

4) At the end: Divide the total by the # of points

So:

1) At the beginning, we initialize MaxVal, MinVal, and Total to the 1st value

2) For each subsequent point (A2 - A5), we add it into the Total, use the max

instruction to determine the minimum value (I know it seems backwards,

but there it is ... It does work this way ... Look carefully at the instruction

description) and the min instruction to determine the maximum value.

3) There's a simple division by a constant (the number of points). Note that

I messed up with the constant value. It should be 5, not 3.

Mike

1) Accumulating a total of the points

2) Determining the maximum of the points

3) Determining the minimum of the points

4) At the end: Divide the total by the # of points

So:

1) At the beginning, we initialize MaxVal, MinVal, and Total to the 1st value

2) For each subsequent point (A2 - A5), we add it into the Total, use the max

instruction to determine the minimum value (I know it seems backwards,

but there it is ... It does work this way ... Look carefully at the instruction

description) and the min instruction to determine the maximum value.

3) There's a simple division by a constant (the number of points). Note that

I messed up with the constant value. It should be 5, not 3.

Mike

Lord Steve

03-06-2007, 01:43 AM

Mike Green said...

I messed up with the constant value. It should be 5, not 3.

Did I miss something?· If you have 5 values and you toss the minimum and maximum values...you have 3 left over.· So, the average of 3 values is the sum divided by...3, not 5.

I messed up with the constant value. It should be 5, not 3.

Did I miss something?· If you have 5 values and you toss the minimum and maximum values...you have 3 left over.· So, the average of 3 values is the sum divided by...3, not 5.

Mike Green

03-06-2007, 01:48 AM

Lord Steve,

Thanks. You're absolutely correct. I forgot about the "tossing the max and min values". Oh well, I guess I'm more confused than usual today.

Mike

Thanks. You're absolutely correct. I forgot about the "tossing the max and min values". Oh well, I guess I'm more confused than usual today.

Mike